Temperature vs. activation energy
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Temperature vs. activation energy
How does temperature affect rate constant k? Does an increase in temperature cause an increase in the rate constant?
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Re: Temperature vs. activation energy
Yes. If you increase T = more collisions = increased rxn rate (knowing rate = k[A]) = increased k
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Re: Temperature vs. activation energy
Just because we are increasing the number of collisions, how does this correlate to a decrease in activation energy? I thought that is something a catalyst does.
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Re: Temperature vs. activation energy
As the temperature increases, the amount of energy in the system increases. This energy is then used to overcome the activation energy
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Re: Temperature vs. activation energy
Yes, an increase in temperature means an increase in the energy within the system, which in turn increases the reaction rate.
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Re: Temperature vs. activation energy
As the temperature increases, the energy of the system also increases
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Re: Temperature vs. activation energy
Yes, an increase in temperature causes an increase in the rate constant.
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Re: Temperature vs. activation energy
When you increase the temperature, this results in more collisions between particles. This will lead to an increase in K.
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Re: Temperature vs. activation energy
Temperature affects K depending on the type of reaction. If the reaction is exothermic, the more temperature increases the lower K will get because the production of reactants are favored. If the reaction is endothermic, the more temperature increases the higher K will get because the formation of products are favored. Hope this helps!
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Re: Temperature vs. activation energy
As T increases, so too does K. As a result, increased T leads to more activation energy as a result of more collisions.
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Re: Temperature vs. activation energy
An increase in temperature (T) causes more collisions. This increases the reaction rate which is why k increases when the temperature does.
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Re: Temperature vs. activation energy
On the equation sheet, there is also the equation: k = A * exp(-Ea/RT). If you examine this reaction, you can rewrite it as k = A * 1/exp(Ea/RT). The bigger T becomes, the smaller exp(Ea/RT) becomes, and the smaller the denominator of the fraction becomes, the bigger 1/exp(Ea/RT) becomes, leading to a larger k value.
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Re: Temperature vs. activation energy
Yes an increase in temperature will lead to an increase in K because it causes an increase in collisions.
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Re: Temperature vs. activation energy
If temperature increases, there are more collisions, thus the rate constant increases.
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Re: Temperature vs. activation energy
If I remember correctly, yes, the relationship is proportional. An increase in T will result in an increase in K.
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Re: Temperature vs. activation energy
The relationship between temperature and the reaction rate is proportional; if you increase the temperature, you increase the reaction rate
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Re: Temperature vs. activation energy
Yes! If you look at the Arrhenius equation, , you can clearly see how temperature affects the rate constant. If the temperature of the reaction is higher then the power to which e is multiplied will be a smaller negative number (aka more positive), and therefore the value of k will increase. Hope this helps.
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Re: Temperature vs. activation energy
As others have stated above, an increase in temperature increases the rate constant, k. Similarly, a decrease in temperature decreases k.
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Re: Temperature vs. activation energy
An increase in temperature increases the rate constant K. This is because when temperature increases, there are more collisions in the given chemical reaction. As a result, products are formed faster, meaning the concentration increases. Since this is the numerator in a rate constant, this means that the rate constant increases.
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Re: Temperature vs. activation energy
Increase in temperature leads to an increase in energy in the system and it also helps create more products from the reaction which affects and increases k
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Re: Temperature vs. activation energy
temperature and reaction rate have a direct relationship; an increase in temperature results in an increase in reaction constant k
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Re: Temperature vs. activation energy
Hi, when temperature increases there is a corresponding increase in energy which causes k to increase as well.
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Re: Temperature vs. activation energy
Increase in T will increase K because the atoms will be more likely to collide
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Re: Temperature vs. activation energy
A greater temperature means more collisions and an increased rate of reaction.
Re: Temperature vs. activation energy
Increasing the temperature causes the molecules to react with more kinetic energy. This increases the probability of collisions between molecules. Therefore, this increases the rate of the reaction because there are more molecules with enough kinetic energy to pass the activation energy barrier.
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Re: Temperature vs. activation energy
Increasing the temperature does cause an increase in k, as increasing the temperature increases the energy in the reaction, therefore causing an increased amount of collisions that speed up the reaction.
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