How do we solve for the activation of a reverse reaction?:
A certain reaction has an enthalpy of deltaH=34 kJ and an activation energy of Ea=66 kJ.
What is the activation energy of the reverse reaction?
Achieve #17 Weeks 9 and 10
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Re: Achieve #17 Weeks 9 and 10
Postby Ramya_Paravastu_1H » Sun Mar 06, 2022 10:08 pm
Your delta H value tells us that the reaction is endothermic. So, in the reverse reaction, you want to get from the products to the reactants. The products are at 34kJ, and the activation energy is 66 kJ, so the reactants would be 66-34kJ.
Last edited by Ramya_Paravastu_1H on Sun Mar 06, 2022 11:04 pm, edited 4 times in total.
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Re: Achieve #17 Weeks 9 and 10
Postby Yalit Gonzalez 1A » Sun Mar 06, 2022 10:30 pm
So we know that the activation energy is to get reactants into products, so in your case 66kJ. But as we see, when this reaction happens, delta H=34, so the reaction is endothermic. Your products sit at 34kJ, but the total activation energy is 66kJ, so in order to get back to reactants, the reverse reaction will then be 66-34=answer
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