2011 Final Q8C

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Rachel Tat 3E
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2011 Final Q8C

Postby Rachel Tat 3E » Fri Mar 11, 2016 3:45 pm

In this problem, we are asked to draw the most stable conformation for cis-1-ethyl-2-methylcyclohexane. Why is there a cis if the cyclo hexane does not have the -ene suffix indicating a double bond?

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Re: 2011 Final Q8C

Postby Chem_Mod » Fri Mar 11, 2016 5:43 pm

cycloalkanes can have cis and trans conformations. If 2 substituents are on the same side of the ring (i.e. both above the ring or both below the ring) then they are cis to each other. If 1 substituent is point up in the ring and the other is pointing down/ if one is above and the other is below, then they are trans to each other.


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