lnk=G/-RT

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Ai-nhi Tran 3A
Posts: 20
Joined: Fri Sep 25, 2015 3:00 am

lnk=G/-RT

Postby Ai-nhi Tran 3A » Sun Mar 06, 2016 9:56 pm

How does the change of temperature (increase or decrease) affect the K?
What does the value of Keq (high or low) tell you about the molecules' conformations?

Joyce Xiong 4C
Posts: 22
Joined: Fri Sep 25, 2015 3:00 am

Re: lnk=G/-RT

Postby Joyce Xiong 4C » Sun Mar 06, 2016 10:11 pm

Hey there!

As temperature decreases, Keq will increase, and when the temperature increases, Keq will decrease. The Keq tells you the ratio between two conformations (how many of the molecules in one conformation vs how many will be in the second/other conformation). In the example Dr. Lavelle gave us, the two conformations were Gauche Butane and Anti Butane where Gauche=Conformation 1 and Anti=Conformation 2. The Keq was 4.6. Because the Keq was calculated by [Conformation 2/Conformation 1], that means the the ratio 4.6 means for every 4.6 butanes in the Anti Conformation, there is in the Gauche Conformation. So depending on you assign as conformation for future problems, the Keq would be the number of conformation 2 molecules you get for one conformation 1 molecule. When Keq is bigger than 1, like in the example, there is more of conformation 2 that conformation 1, and when it is smaller, there is more conformation 1 molecules than conformation 2 molecules.

Hope this helps!


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