Metal Hydroxides and sulfides

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ian_haliburton_1f
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Metal Hydroxides and sulfides

Postby ian_haliburton_1f » Tue Oct 02, 2018 3:55 pm

In the practice problem set of Fundamentals E, there is a question (E15) that requires knowledge about metal hydroxides and sulfides. It seems that if you are given a metal hydroxide’s formula, you can derive a corresponding sulfide through the hydroxide’s molar mass. I am not sure how and why works, so I would appreciate some insight into the structure of these substances and their relationship to one another.

Jeffrey Xiao 4A
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Re: Metal Hydroxides and sulfides

Postby Jeffrey Xiao 4A » Tue Oct 02, 2018 4:11 pm

For that problem, just find the molar mass of (OH)2 which is ~34.014 g/mol, then subtract that number from 74.10 g/mol (the total molar mass of the metal hydroxide) to find the molar mass of the metal. Then using a periodic table, find which element has the molar mass found previously which should be calcium. Finally, then find the molar mass of calcium sulfide. Calcium sulfide has one atom of calcium and one atom of sulfur as calcium has +2 charge and sulfur has +2 charge, so molar mass of CaS is the answer found by adding molar mass of Calcium to molar mass of Sulfur (40.078 + 32.06)g/mol.

Manya Bali 4E
Posts: 66
Joined: Fri Sep 28, 2018 12:23 am

Re: Metal Hydroxides and sulfides

Postby Manya Bali 4E » Tue Oct 02, 2018 4:12 pm

You can find out what metal it is without any complicated concepts!

The problem gives you the molecular formula M(OH)2. We need to find what element M is.

We know that the molar mass of the entire compound is 74.10 g/mol. We don't know what the molar mass of M (the unknown metal) is but we do know the molar masses of oxygen (16.00 g/mol) and hydrogen (1.01 g/mol).

This means that the molar mass of (OH)2 must be 2(16.00)(1.01) or 34.02 g/mol.

Now let's subtract the known molar masses: 74.10 - 34.02 = 40.08 g/mol. This is the molar mass of the unknown metal. We can figure out what the unknown metal is by looking at the periodic table and seeing which element has an atomic weight of 40.08.

Hope this helps!


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