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Converting from mole ratios to empirical formula

Posted: Thu Oct 04, 2018 5:45 pm
by Melody Zhang 3L
For problem F9 (sixth edition), how is the ratio 1 oxygen 2.67 hydrogen and 2.67 carbon converted to the empirical formula C8H8O3? I understand that the ratio is multiplied by three but I don't see how to tell what multiple to multiply the ratio with.

Re: Converting from mole ratios to empirical formula

Posted: Thu Oct 04, 2018 5:50 pm
by Manas_Varma_4B
You want the numbers that are decimals to be as close as possible to a whole number.

In this case:
2.67 x 1 = 2.67 (not close to a whole number)
2.67 x 2 = 5.34 (not close to a whole number)
2.67 x 3 = 8.01 (close to a whole number)

So if you multiply all the mole numbers by 3, you get 3 oxygen, 8 hydrogen, and 8 carbon: C8H8O3

Re: Converting from mole ratios to empirical formula

Posted: Thu Oct 04, 2018 5:52 pm
by Melody Zhang 3L
I see, thanks!