Question L.39, Reaction Stoichiometry

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juliefilice 4A
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Joined: Fri Sep 28, 2018 12:27 am

Question L.39, Reaction Stoichiometry

Postby juliefilice 4A » Sat Oct 06, 2018 2:45 am

Could I get a step by step solution to this problem? I'm not sure where to start.
"A 1.50 g sample of metallic tin was placed in a 26.45 g crucible and heated until all the tin had reacted with the O in air to form an oxide. The crucible and product together were found to weigh 28.35 g. a. What is the empirical formula of the oxide? b. Write the name of the oxide."

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Joined: Fri Sep 28, 2018 12:19 am

Re: Question L.39, Reaction Stoichiometry

Postby yast_27 » Sat Oct 06, 2018 9:02 am

In this problem, you want to figure out the ratio (the empirical formula) between quantity (in mole) of Oxygen (O) and tin (Sn) in the oxide of tin.
The step for this kind of problem are the following:

- calculate the mass of each component:
m (Sn) = 1.50g
m (O) = 28.35g - (26.45 + 1.50 = 27.95 => mass before adding O) = 0.40

-calculate/determine the molar mass of each component:
M(O)= 16.0
M(Sn) = 118.71

- Determine the #mole of each component:
n(Sn) = 1.5/118.71 = 0.0126 mol
n(O) = 0.4/16.00 = 0.025 mol

- Compare the ratio of each component and write the empirical formula:

There is 1 Sn for 2 O => empirical formula = SnO2

I hope that this will help!

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