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Problem L39

Posted: Wed Oct 10, 2018 4:49 pm
by Alex Alonso - 4F
Not entirely sure how to do problem L39:

A 1.50-g sample of metallic tin was placed in a 26.45-g crucible and heated until all the tin had reacted with the oxygen in air to form an oxide. The crucible and product together were found to weigh 28.35 g. (a) What is the empirical formula of the oxide? (b) Write the name of the oxide.

Re: Problem L39

Posted: Wed Oct 10, 2018 5:07 pm
by Chris Freking 2G
The crucible and product together weigh 28.35g.

Subtract the mass of the crucible (26.45g) from the mass of the crucible and the product (28.35g) to get the mass of the product (1.900g).

Since we know we started with 1.500g of Sn, you can subtract that mass from the mass of the product (1.900g) to find the mass of the oxygen, which is 0.4000g.

Then find how many mol of oxgen and tin we have:
0.4000g O * (1 mol O/15.999g O) = 0.0250 mol O
1.500g Sn * (1 mol Sn/118.71g Sn) = 0.0126 mol Sn

Divide both by 0.0126 and the result will be 1Sn:2O, so the resulting compound is:
SnO2
Tin (IV) Dioxide or Tin Dioxide