HW E17 part C

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Sarah Nichols 4C
Posts: 52
Joined: Sat Aug 24, 2019 12:18 am

HW E17 part C

Postby Sarah Nichols 4C » Tue Oct 01, 2019 5:07 pm

This question asks which contains the greater number of moles of atoms, 7.36x10^27 atoms of Ru or 7.36x10^27 atoms of Fe
I was thinking they should contain the same number of atoms, since a mole of atoms of any element contains 6.0221x10^23 atoms, but I'm not sure if I'm thinking about this wrong

Justin Sarquiz 2F
Posts: 106
Joined: Fri Aug 30, 2019 12:15 am

Re: HW E17 part C

Postby Justin Sarquiz 2F » Tue Oct 01, 2019 5:17 pm

Your reasoning is correct. You would take the number of atoms for each element and divide that by 6.022 x 10^23 atoms/mol. The atoms would cancel, and you should get 1.22 x 10^4 mol for each element, so the number of moles is the same.

Vincent Leong 2B
Posts: 207
Joined: Fri Aug 09, 2019 12:15 am

Re: HW E17 part C

Postby Vincent Leong 2B » Tue Oct 01, 2019 5:20 pm

Although all elements have 6.022x10^23 atoms/molecules in 1 mol of substance, they might not all have equal amount of moles. If the numbers differed slightly, you'd have differing amount of moles but I guess for this question, neither element has a greater amount of moles.

Joanne Kang 3I
Posts: 50
Joined: Thu Jul 25, 2019 12:17 am

Re: HW E17 part C

Postby Joanne Kang 3I » Tue Oct 01, 2019 5:28 pm

Yes. This is a trick question, so doing the stoichiometry for each molecule should reveal that they both convert to 1.22x10^4 moles.

Sjeffrey_1C
Posts: 108
Joined: Wed Feb 20, 2019 12:17 am

Re: HW E17 part C

Postby Sjeffrey_1C » Wed Oct 02, 2019 6:08 pm

Your logic is correct! It isn't even necessary to do any calculations for part c. Since the number of atoms of both are the same, the number of moles of each must also be the same.

Arvind 4G
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Re: HW E17 part C

Postby Arvind 4G » Wed Oct 02, 2019 6:59 pm

Yes, you would be correct. It looks like a trick question as for any compound or element, the number of atoms in a mole is constant.


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