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Not quite sure, but I think that because oxygen has a charge of -2 on the periodic table and there are 2 oxygen atoms, you need tin to have a charge of 4 in order to balance it out. Tin is a transitional metal, meaning it does not have a set charge, so you need to look at the charge and number of oxygen to determine tin's charge.
Tin is an element that exists in more than one oxidation state, meaning its ions could carry different charges. For tin specifically, it could be Sn2+or Sn4+. But since oxygen's oxidation number is -2 and there are two oxygen ions present in SnO2, for the net charge to equal 0, the tin ion must carry a charge of +4. Therefore, by following nomenclature rules, SnO2 should be written as Tin(IV) Oxide, with the Roman numeral IV representing that the tin ion has a charge of +4.
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