## L. 39

Kelly Cai 4D
Posts: 55
Joined: Sat Jul 20, 2019 12:17 am

### L. 39

A 1.50 g sample of metallic tin was placed in a 26.45 g crucible and heated until all the tin had reacted with the oxygen in air to form an oxide. The crucible and product together were found to weigh 28.35 g.
(a.) What is the empirical formula of the oxide?
(b.) Write the name of the oxide.

Chem_Mod
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### Re: L. 39

For part a, you would find the percentages of each reactant, assume 100g, and then solve for the empirical formula from there. For part b, you would have to write out the chemical reaction to determine the product.

Jessica Li 4F
Posts: 115
Joined: Fri Aug 09, 2019 12:16 am

### Re: L. 39

To elaborate on the previous answer, for part a you want to make sure to subtract the crucible weight from the total weight to find the weight of the product itself, and then take the given mass of tin to find the percentages of both tin and oxygen, as they are the only two elements involved in the product.
For part b, after you've determined the empirical formula of the compound, and since oxygen is always a -2 charge, you can figure out what charge tin is in this case and write tin (Roman numeral of charge) oxide. Since the formula comes out to SnO2, tin has a +4 charge, so the compound would therefore be called tin(IV) oxide.
Hope this helps!