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L35

Posted: Fri Oct 02, 2015 10:22 am
by Jasmine Lam 1I
Sodium bromide, NaBr, which is used to produce AgBr for use in photographic film, can itself be prepared as follows.
FeBr+Br2 ---> FeBr2
FeBr2+Br2---> Fe3Br8
Fe3Br8+Na2CO3-->NaBr+CO2+FE3O4
What mass of iron, in kg, is needed to produce 2.50t of NaBr?

Re: L35

Posted: Fri Oct 02, 2015 2:43 pm
by Helen T 2G
First, you must convert the 2.50 t of NaBr to grams using the conversion factor 1.0 x 10^6 grams = 1 ton. Then you find the molar mass of NaBr (102.89g) and divide the grams of NaBr by NaBr's molar mass. Next, find the mole ratio between Fe and NaBr which is 3 mol Fe: 8 mol NaBr (don't forget to make sure all the equations are balanced before proceeding with the problem). Lastly, multiply by the molar mass of Fe (55.84g) which will result in 5.09 x 10^5g of Fe which is equivalent to 509 kg of Fe.

Re: L35

Posted: Thu Oct 04, 2018 12:18 pm
by Hadji Yono-Cruz 2L
Helen T 2G wrote:First, you must convert the 2.50 t of NaBr to grams using the conversion factor 1.0 x 10^6 grams = 1 ton. Then you find the molar mass of NaBr (102.89g) and divide the grams of NaBr by NaBr's molar mass. Next, find the mole ratio between Fe and NaBr which is 3 mol Fe: 8 mol NaBr (don't forget to make sure all the equations are balanced before proceeding with the problem). Lastly, multiply by the molar mass of Fe (55.84g) which will result in 5.09 x 10^5g of Fe which is equivalent to 509 kg of Fe.


Where did you find the conversion factor to be 1.0 x 10^6 grams = 1 ton? When I converted 1 ton to grams on Google it says it is 907185 grams.

Re: L35

Posted: Mon Oct 08, 2018 3:04 pm
by DavidEcheverri3J
904928548 wrote:
Helen T 2G wrote:First, you must convert the 2.50 t of NaBr to grams using the conversion factor 1.0 x 10^6 grams = 1 ton. Then you find the molar mass of NaBr (102.89g) and divide the grams of NaBr by NaBr's molar mass. Next, find the mole ratio between Fe and NaBr which is 3 mol Fe: 8 mol NaBr (don't forget to make sure all the equations are balanced before proceeding with the problem). Lastly, multiply by the molar mass of Fe (55.84g) which will result in 5.09 x 10^5g of Fe which is equivalent to 509 kg of Fe.


Where did you find the conversion factor to be 1.0 x 10^6 grams = 1 ton? When I converted 1 ton to grams on Google it says it is 907185 grams.


The problem is referring to Metric Tons, not US Tons, since US Tons (the one you Googled) is Imperial System, while Metric Tons are Metric System, which is the system commonly used throughout chemistry. Hope this helped!

Re: L35

Posted: Thu Oct 22, 2020 9:51 pm
by lwon Dis2I
Why does this problem give us three chemical reaction equations and not just one?