## dz orbital

$H_{\psi }=E_{\psi }$

1-D: $E_{TOTAL}\psi (x)=E_{k}\psi (x)+V(x)\psi(x)=-\frac{h^{2}}{8\pi ^{2}m}\frac{d^{2}\psi(x)}{dx^{2}}+V(x)\psi(x)$

josephyim1L
Posts: 61
Joined: Fri Sep 28, 2018 12:15 am

### dz orbital

In class today, Lavelle mentioned that the cone around the dz orbital is a nodal plane as well as an area of reactivity, can someone explain this in more detail?

Anushi Patel 1J
Posts: 61
Joined: Fri Sep 28, 2018 12:19 am
Been upvoted: 1 time

### Re: dz orbital

I think he meant that the area within the cone up to the boundary of the cone is an area of reactivity, but the cone itself is a nodal plane.

Irene Zhou 1E
Posts: 73
Joined: Fri Sep 28, 2018 12:18 am

### Re: dz orbital

The cone itself is a nodal plane because the probability of locating an electron in that plane is zero.