## Schrodinger for exam

$H_{\psi }=E_{\psi }$

1-D: $E_{TOTAL}\psi (x)=E_{k}\psi (x)+V(x)\psi(x)=-\frac{h^{2}}{8\pi ^{2}m}\frac{d^{2}\psi(x)}{dx^{2}}+V(x)\psi(x)$

Katherine Chhen 3I
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### Schrodinger for exam

Would we need to know the schrodinger equation conceptually for an exam?

KeyaV1C
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### Re: Schrodinger for exam

I don’t think we need to know it in too much detail. I’m pretty sure we only need to know it in the context of the quantum numbers that correspond to a solution for a wave function.

Alexandra Bartolome 2H
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### Re: Schrodinger for exam

I would assume so since Professor Lavelle's outline for The Quantum World lists that we should understand the relationship between Schrodinger's Equation, wave functions, and orbitals.

Kate Osborne 1H
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### Re: Schrodinger for exam

Yeah I don’t think we need to know absolutely everything about it but understanding how it relates to the other things that were mentioned already!

kevinolvera1j
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### Re: Schrodinger for exam

Understanding the equation at conceptual level is important but understanding the finer details of the equation is not as important for this level of chemistry

Jennifer Yang 3F
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### Re: Schrodinger for exam

I believe we only have to understand the general concept of the equation.

Nuoya Jiang
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### Re: Schrodinger for exam

I think we only need to understand the relationship between Schrodinger's equation and quantum numbers. After all, the emphasis of Focus 1 (Quantum World) is still on the model of electrons and properties of light.

Daniel Yu 1E
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### Re: Schrodinger for exam

So what exactly is the relationship between Schrodinger's Equation, wave functions, and orbitals?

ramiro_romero
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### Re: Schrodinger for exam

Yes, at the very least understand its purpose/application.

DLee_1L
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### Re: Schrodinger for exam

I think the relationship is that Schrödinger's equation mathematically maps out the possible area that an electron can be in (an orbital) when it acts as a wave.

Xavier Herrera 3H
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### Re: Schrodinger for exam

I suppose we should know that solving Schrodinger's equation would give you a range of positions and momentums for a wave. But due to the uncertainty principle, the equation won't give you an exact answer for both position and momentum. The orbital of an electron would definitely matter to find its position, since orbitals have certain probability regions.

Andrew Yoon 3L
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### Re: Schrodinger for exam

I think the concept an how the equation is used is important for us and for the exam.

Edwin Liang 1I
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### Re: Schrodinger for exam

I don't think so. Understanding basic principles that support what we have learned is enough I think.

isha dis3d
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### Re: Schrodinger for exam

Schrodinger's equation is important because wavefunctions of certain electrons are obtained as solutions to this equation. For example, atomic orbitals would be one.

Shrinidhy Srinivas 3L
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### Re: Schrodinger for exam

Dr. Lavelle just talked about it in his lecture! You don't need to know the actual equation, but you just need to understand it conceptually. You also need to understand how Schrodinger's equation links to orbitals. Hope this helps!

Libby Dillon - 1A
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### Re: Schrodinger for exam

I believe we only need to understand where Schrodinger's equation comes from and the underlying concepts it represents, not how to actually find values from it. We should know how it connects to Heisenberg's equation and the role it plays in orbitals. I am unsure how we will be tested on the concept though.

SahajDole_1C
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### Re: Schrodinger for exam

Schrodinger may be referenced, but I do not think it'll be on the exam too much.

Kimiya Aframian IB
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### Re: Schrodinger for exam

Daniel Yu 1E wrote:So what exactly is the relationship between Schrodinger's Equation, wave functions, and orbitals?

Hi! Please correct me if I am wrong but I am pretty sure that the Schrodinger Equation is explaining how the position of electrons in orbitals is not going to be completely accurate (Heisenberg) and that the electrons act as waves (De Broglie). This is why we use the sin (or cos) function to represent it. Keep in mind that psi is the height of the wave and the position is (x,y,z) because it is in the 3D world so must have a 3D plane. Also, Schrodinger's Equation in terms of describing psi^2 connects back to the Heisenberg equation because it is the probability of finding an electron (this is a squared value, meaning it is always positive which makes sense because we know that probabilities cannot be negative). Also, the wavelike properties that DeBroglie discovered are apparent in Schrodinger's Equation because Hx(psi)=Ex(psi), showing that there is a direct relationship between energy and the Hamiltonian (double derivative).
Hope this helps!

Keerthana Sundar 1K
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### Re: Schrodinger for exam

"Also, the wavelike properties that DeBroglie discovered are apparent in Schrodinger's Equation because Hx(psi)=Ex(psi), showing that there is a direct relationship between energy and the Hamiltonian (double derivative)."

I think I'm still kind of confused about the relationship between energy and the Hamiltonian? What does the Hamiltonian represent for an electron, and how does this relate to the energy of the electron? It would be great if you could explain this concept to me further, thanks!

Posts: 101
Joined: Wed Sep 30, 2020 9:35 pm

### Re: Schrodinger for exam

I went to a UA session today, and he said he thinks we do not need to know much for this midterm, and just discussed the s and p orbitals and how there are certain areas of a higher probability of finding electrons within them.

Ximeng Guo 2K
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### Re: Schrodinger for exam

Thank you for the explanations!