1B.25

[Charlotte Messier 3C]

What is the minimum uncertainty in the speed of an electron confined within a lead atom of diameter 350 pm? Model the atom as a one-dimensional box with a length equal to the diameter of the actual atom.

[Michelle Meza 3B]

To get you started, this problem will require you to use Heisenberg's Indeterminacy Equation which is Delta p x Delta x >= h/(4pi).
You need to arrange it in a way you find Delta p and plug the known values into the Heisenberg equation and solve for Delta p.

[Emily 3I]

First, you'd use the Heisenberg equation and rearrange the values to solve for uncertainty in speed (remember p=mv). Then plug in what you know m=mass of electron, indeterminacy in position (350 pm converted to meters), the h constant, and pi. There is also a detailed solution in a pdf on Bruin Learn if you'd like to see the math after you attempt to solve it!

[606045283]

What is the minimum uncertainty in the speed of an electron confined within a lead atom of diameter 350 pm? Model the atom as a one-dimensional box with a length equal to the diameter of the actual atom.
From what I remember during discussion the way in which you approach this question is that you remember that what you're solving for is the minimum uncertainty in the speed of an electron. Now, from the question/problem you can grasp that you must convert the 350pm into meters. Second step, remember the equation delta X times delta p is greater than or equal to h/4pi, by remembering this equation, you can use it to find the velocity. You do this because as mentioned in discussion momentum is related to velocity. So, at the end you have the equation delta V is greater than or equal to h/4pi*delta X*radium atom diameter that's now in meters * the mass of an electron. That is how you solve the equation, the answer at the end should remain in the delta v is greater than or equal to the minimum uncertainty.