Use of Rydberg formula  [ENDORSED]

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Use of Rydberg formula

Postby Rob_Carter_1L » Mon Oct 10, 2016 9:55 am

During lecture, Professor Lavelle mentioned that he prefers not to use the Rydberg formula, rather E= hR/(n1)^2 - hR/(n2)^2. Is this what we should use on the test?

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Re: Use of Rydberg formula  [ENDORSED]

Postby paulapedrani » Mon Oct 10, 2016 12:21 pm

My TA said we could use either one, but since you can get partial credit in the quizzes, he recommended we use the one Lavelle was talking about so that there are less chances of making a mistake and more chances of getting partial credit if we do!

An Dang 3F
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Re: Use of Rydberg formula

Postby An Dang 3F » Sat Oct 21, 2017 5:11 pm

You can always derive the Rydberg Equation from E= hR/(n1)^2 - hR/(n2)^2 by dividing each side of the equation by h because the formula for frequency is E= hv.

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