Use of Rydberg formula [ENDORSED]

[Rob_Carter_1L]

During lecture, Professor Lavelle mentioned that he prefers not to use the Rydberg formula, rather E= hR/(n1)^2 - hR/(n2)^2. Is this what we should use on the test?

[paulapedrani]

My TA said we could use either one, but since you can get partial credit in the quizzes, he recommended we use the one Lavelle was talking about so that there are less chances of making a mistake and more chances of getting partial credit if we do!

[An Dang 3F]

You can always derive the Rydberg Equation from E= hR/(n1)^2 - hR/(n2)^2 by dividing each side of the equation by h because the formula for frequency is E= hv.