## Application

$E_{n}=\frac{h^{2}n^{2}}{8mL^{2}}$

Daniel Vo 1B
Posts: 45
Joined: Thu Jul 13, 2017 3:00 am

### Application

Hi, sorry, I'm kind of struggling to understand how the equation works; can someone explain the equation in physical example? Like if one variable grows bigger, what happens to the others, and what would that mean?

Chem_Mod
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Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 428 times

### Re: Application

As the length L gets larger, the E gap becomes smaller, and finally goes to the classical limit: the energy is almost continuous.

rkang00
Posts: 69
Joined: Fri Sep 28, 2018 12:25 am

### Re: Application

Okay but when do you use the equation for? I never fully understood where to use it (if anyone knows if it explains in the textbook let me know)

904936893
Posts: 62
Joined: Fri Sep 28, 2018 12:29 am

### Re: Application

I believe there is an example in the textbook (6th edition) on page 23. It goes through how to calculate the energies of a particle in a box.

britthanul234
Posts: 51
Joined: Wed Sep 18, 2019 12:21 am

### Re: Application

When length increases, the energy gap decreases.