Balancing Chem Eq Audio Visual Post-Assess #8

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katherine_arnaud_1F
Posts: 9
Joined: Fri Jul 22, 2016 3:00 am

Balancing Chem Eq Audio Visual Post-Assess #8

Postby katherine_arnaud_1F » Thu Sep 29, 2016 9:31 am

Hello!

#8 of the AV post assessment asked for the net number of moles of gas produced.

the balanced equation is: 4 C4H10(g)+ 26 O2(g) -> 16 CO2(g)+ 20 H2O(g)

I believe the net number of moles of gas produced is either 5 or 6 (because those were the options.)

We begin with 4 moles of C4H10.

Can someone explain what the net number of moles of gas produced is referring to?
Also, how to get the answer.

Thanks!

Alex_Wagas_3K
Posts: 16
Joined: Tue Nov 25, 2014 3:00 am

Re: Balancing Chem Eq Audio Visual Post-Assess #8

Postby Alex_Wagas_3K » Thu Sep 29, 2016 10:17 am

To calculate the net number of moles of gas produced, you take the difference of the sum of the coefficients of the reactant by the sum of the coefficients of the product. Here is an illustrated format of how you would calculate it:

Sum of Coefficients of the Product - Sum of Coefficients of the Reactant = Net Number of Moles of Reaction

For this particular example, you would do the following:
Sum of the Coefficients of the Product --> 16 + 20 = 36
Sum of the Coefficients of the Reactant --> 4 + 26 = 30

Therefore...

36 - 30 = 6 moles

Hopefully this helps and explains how to solve the problem. If anyone else would like to elaborate on this post it would be greatly appreciated!

katherine_arnaud_1F
Posts: 9
Joined: Fri Jul 22, 2016 3:00 am

Re: Balancing Chem Eq Audio Visual Post-Assess #8

Postby katherine_arnaud_1F » Thu Sep 29, 2016 3:04 pm

Thank you this is absolutely perfect!


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