Fundamental H11

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Jacinda Wollenweber 1D
Posts: 22
Joined: Wed Nov 16, 2016 3:02 am

Fundamental H11

Postby Jacinda Wollenweber 1D » Sun Jul 02, 2017 10:37 pm

I was hoping someone could explain what methods you used to balance the equation. I balanced iron first, but then got confused with how to balance the rest. How did you figure out that 4 moles of Co and Co2 were needed?

Kyle Sheu 1C
Posts: 87
Joined: Fri Jun 23, 2017 11:39 am

Re: Fundamental H11

Postby Kyle Sheu 1C » Tue Jul 04, 2017 8:58 pm

Since we have CO on one side of the equation and Co2 on the other side, we can't simply balance the oxygens by having 9/2C02 on the products side, since the carbons would then be unbalanced. So what I did was set up a small equation representing the number of oxygen atoms on each side (where x is the stoichiometric coefficient we place in front of CO and CO2:

4+x=2x (4 O's from the iron(III) oxide, and O's in CO and CO2 exist in a 1:2 ratio, hence the x and 2x)
4=x

Wu Yuchen A1
Posts: 24
Joined: Thu Jun 29, 2017 3:00 am

Re: Fundamental H11

Postby Wu Yuchen A1 » Fri Jul 07, 2017 11:11 pm

To balance equations we learn currently, I recommend you to first find the element exist only once on both sides of equation and you can determine the scale of these two parts of equation. Them with the setted scale, it's easy to balance the remaining stuffs.


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