When a problem says that Molecule A reacts with Element B in the presence of C, we don't have to write/include C in the equation right? For instance, in problem H7, the problem is:
Write a balanced equation for [...] the reaction of ammonia gas with oxygen gas at high temperatures in the presence of a copper metal catalyst produces the gases water and nitrogen dioxide.
Since copper is just a catalyst, we don't have to write it on the equation right?
So the answer will be: 4NH3 (g) + 7 O2 (g) ---> 6 H2O (g) + 4 NO2 (g)...
Is this right?
H7 // Book Problem Clarification
Moderators: Chem_Mod, Chem_Admin
Re: H7 // Book Problem Clarification
Yes, that is correct. If I'm right, catalysts are not consumed during reactions, but only serve to speed up the rate of the chemical reaction. In other words, they are not a reactant or a product, so you would not include them in the chemical equation! Hope that helps!
-
- Posts: 67
- Joined: Fri Sep 29, 2017 6:04 am
Re: H7 // Book Problem Clarification
You do not include the catalyst in the equation because its only purpose is to speed up the process of the reaction.
-
- Posts: 52
- Joined: Thu Jul 13, 2017 2:00 am
- Been upvoted: 1 time
Re: H7 // Book Problem Clarification
Although catalysts are not necessary to include in a chemical reaction, I think they are still often referenced by writing them above the arrow, no?
-
- Posts: 53
- Joined: Fri Sep 29, 2017 6:04 am
Re: H7 // Book Problem Clarification
Yeah, you reference the catalyst by putting it above the arrow, but you wouldn't include it in the actual chemical equation.
Return to “Balancing Chemical Reactions”
Who is online
Users browsing this forum: No registered users and 1 guest