## Percent yield [ENDORSED]

Simrina Desar Dis 1H
Posts: 49
Joined: Fri Sep 29, 2017 7:04 am

### Percent yield

For M1 the question asks what is the percent yield of hydrazine? The question gives the net ionic equation for the reaction. I was wondering if the net ionic equation plays a role in this problem since some of the dissolved ions are not written.

Hannah Guo 3D
Posts: 56
Joined: Fri Sep 29, 2017 7:06 am

### Re: Percent yield

You don't need to care about other solutes that are not involved in the reaction since they have no influence on the reaction.
The following steps are what you need to solve the problem:
1. converting 35 g ammonia to moles
2. calculating the expected moles of Hydrazine in the product
3. converting the moles of Hydrazine to grams (expected mass of hydrazine)
4. calculating the percent yield = (25.2 g/expected mass of hydrazine)*100%

Hope it helps!

JELCI_BARRAZA_1C
Posts: 17
Joined: Wed Sep 21, 2016 3:00 pm

### Re: Percent yield

question: how do I calculate percent yield?

Alexa_Henrie_1I
Posts: 61
Joined: Fri Sep 29, 2017 7:03 am

### Re: Percent yield

percent yield= actual yield (which will be given to you)/theoretical yield

mayapartha_1D
Posts: 50
Joined: Fri Sep 29, 2017 7:07 am

### Re: Percent yield  [ENDORSED]

Hi Jelci!

To calculate percent yield, all you have to do is divide the actual yield by theoretical yield. This will give you a decimal value, which you can then multiply by 100 to get the percent value. To think about this in an easier way just consider how much of your theoretical yield you have produced!

Hope this helps,
Maya

Yvonne Kamau 1H
Posts: 1
Joined: Fri Sep 29, 2017 7:06 am

### Re: Percent yield

If it so happens that the theoretical yield and the actual yield have a difference of about 0.99 are we allowed to assume that the actual yield and theoretical yield is the same ?

Kaelie Blanes-Ronda 2L
Posts: 42
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 1 time

### Re: Percent yield

In most cases even though the difference is small there is still a difference, so you shouldn't assume that the theoretical and actual yield are the same unless it's stated otherwise. If anything this proves that your experiment was highly precise.