What’s the quickest way to approaching writing a balanced equation with only one given compound?

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Genisis Cabral
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What’s the quickest way to approaching writing a balanced equation with only one given compound?

Postby Genisis Cabral » Fri Oct 06, 2017 7:34 pm

When focusing on balanced equations, there are times when I encounter the need to write a balanced chemical equation after only receiving one compound in the given information. In these cases what is the quickest approach/method to write the correct reactants and products?
Such clarification will be very helpful!!

Michelle Pham_3H
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Joined: Fri Sep 29, 2017 7:07 am

Re: What’s the quickest way to approaching writing a balanced equation with only one given compound?

Postby Michelle Pham_3H » Fri Oct 06, 2017 7:41 pm

This only answers your question in regards to combustion. In a combustion reaction, oxygen is always part of the reactants, while water and carbon dioxide are always given off as products. All three are normally in the form of a gas. Combustion reactions are often indicated through burning, metabolism, oxidation, or oxidative metabolism.

Johann Park 2B
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Re: What’s the quickest way to approaching writing a balanced equation with only one given compound?

Postby Johann Park 2B » Fri Oct 06, 2017 9:38 pm

Usually in these cases, the mass of the two products will be given, as well as the mass of the unknown compound. Normally this will be a combustion question. In combustion, you have O2 reacting with the compound to produce Carbon Dioxide and Water vapor. For example, if you have the oxidation: CxHyOz + O2 -> CO2 + H2O, you will have the mass of CO2 and H2O in grams. You will use molar weights and mole ratios to find the mols & then grams of the elements in the unknown compound, and finally find the ratio of moles to complete the unknown compound.

Eli Aminpour 2K
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Re: What’s the quickest way to approaching writing a balanced equation with only one given compound?

Postby Eli Aminpour 2K » Fri Oct 06, 2017 11:20 pm

When balancing a combustion equation, try to start by balancing the carbon and hydrogen on the product side to match the reactants. Since its a combustion, you can always add more to the O2 (reactant) to balance it.


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