## What’s the quickest way to approaching writing a balanced equation with only one given compound?

Genisis Cabral
Posts: 20
Joined: Fri Sep 29, 2017 7:07 am

### What’s the quickest way to approaching writing a balanced equation with only one given compound?

When focusing on balanced equations, there are times when I encounter the need to write a balanced chemical equation after only receiving one compound in the given information. In these cases what is the quickest approach/method to write the correct reactants and products?
Such clarification will be very helpful!!

Michelle Pham_3H
Posts: 26
Joined: Fri Sep 29, 2017 7:07 am

### Re: What’s the quickest way to approaching writing a balanced equation with only one given compound?

This only answers your question in regards to combustion. In a combustion reaction, oxygen is always part of the reactants, while water and carbon dioxide are always given off as products. All three are normally in the form of a gas. Combustion reactions are often indicated through burning, metabolism, oxidation, or oxidative metabolism.

Johann Park 2B
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Joined: Thu Jul 27, 2017 3:01 am
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### Re: What’s the quickest way to approaching writing a balanced equation with only one given compound?

Usually in these cases, the mass of the two products will be given, as well as the mass of the unknown compound. Normally this will be a combustion question. In combustion, you have O2 reacting with the compound to produce Carbon Dioxide and Water vapor. For example, if you have the oxidation: CxHyOz + O2 -> CO2 + H2O, you will have the mass of CO2 and H2O in grams. You will use molar weights and mole ratios to find the mols & then grams of the elements in the unknown compound, and finally find the ratio of moles to complete the unknown compound.

Eli Aminpour 2K
Posts: 50
Joined: Fri Sep 29, 2017 7:04 am

### Re: What’s the quickest way to approaching writing a balanced equation with only one given compound?

When balancing a combustion equation, try to start by balancing the carbon and hydrogen on the product side to match the reactants. Since its a combustion, you can always add more to the O2 (reactant) to balance it.