Net Number of moles produced  [ENDORSED]

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Glendy Gonzalez 1A
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Joined: Fri Sep 29, 2017 7:07 am

Net Number of moles produced

Postby Glendy Gonzalez 1A » Sat Dec 09, 2017 2:34 pm

Based on a balanced chemical equation, how can you calculate the net number of moles of gas produced?

Carlos Gonzales 1H
Posts: 50
Joined: Fri Sep 29, 2017 7:05 am
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Re: Net Number of moles produced

Postby Carlos Gonzales 1H » Sat Dec 09, 2017 2:46 pm

After balancing and finding the total moles on the reactants and the products side, the net number of moles will be the moles on the products side - the moles on the reactants side.

Thompson W 2C
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Re: Net Number of moles produced  [ENDORSED]

Postby Thompson W 2C » Mon Dec 11, 2017 1:48 am

Net number of moles would be the total number of moles on the product side minus the total number of moles on the reactant side.

Raquel Floyd 1K
Posts: 19
Joined: Wed Sep 21, 2016 2:59 pm

Re: Net Number of moles produced

Postby Raquel Floyd 1K » Thu Apr 05, 2018 12:03 pm

So given this example problem (taken from the post-assessment on balancing equations):
"During a summer camping weekend 4 moles of butane (C4H10) gas were used for cooking. Chose the right balanced equation for the combustion of 4 moles of butane gas. What is the net number of moles of gas produced?"
Would the correct answer be:
4C4H10(g) + 26O2(g) --> 16CO2(g) + 20H2O (g); 6?
I am fairly confident that I balanced the equation correctly, I just want to be sure I understand and applied the concept of how to find the net number of moles produced, which would be 6?


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