Balancing Equations With Rational Coefficients  [ENDORSED]

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Perla Cervantes_1G
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Joined: Fri Apr 06, 2018 11:02 am

Balancing Equations With Rational Coefficients

Postby Perla Cervantes_1G » Mon Apr 09, 2018 4:04 pm

What is the balanced chemical equation?

2Na+2H20------> 2NaOH+H2

I understand that mass cannot be created, or destroyed--thus, an element must have the same quantity in the reactant and product side. In this example Professor Lavelle used a fraction (13/2) to balance this equation. However, I do not understand why he used a fraction instead of a whole number. Can someone please explain this?

ErinKim1I
Posts: 31
Joined: Fri Apr 06, 2018 11:03 am

Re: Balancing Equations With Rational Coefficients

Postby ErinKim1I » Mon Apr 09, 2018 4:09 pm

If he used a fraction w/ denominator 2, he probably multiplied the entire equation by 2 to create whole numbers afterwards

Jaquelinne Rodriguez-Lopez 1L
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Re: Balancing Equations With Rational Coefficients

Postby Jaquelinne Rodriguez-Lopez 1L » Mon Apr 09, 2018 8:01 pm

The fractions are quite confusing. In the video, he does mention that he does not want to use "6.5" because it is not a whole number. by writing 6.5 as a fraction, 13/2, we are able to remove the 2 from the fraction through multiplication. Because we multiply by 2 on the reactant side, we also multiply by 2 on the right side. this will remove the 2 from the numerator (leaving 13/1 or 13) and double the numbers in front of the other elements.

Yeo Bin Yook 1K
Posts: 30
Joined: Fri Apr 06, 2018 11:05 am

Re: Balancing Equations With Rational Coefficients  [ENDORSED]

Postby Yeo Bin Yook 1K » Sat Apr 14, 2018 9:37 pm

Initially he used the fraction to balance out the equation mathematically, but later he mentioned that all stoichiometric coefficients must be whole number so he multiplied the whole thing by 2 and acquired whole numbers!


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