Test 1 Q3

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Bree Perkins 1E
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Joined: Fri Apr 06, 2018 11:04 am

Test 1 Q3

Postby Bree Perkins 1E » Sat May 05, 2018 1:38 pm

Hi, I was wondering if someone could help me balance and equation. The hard part for me to understand is when you have to use a fraction and the multiply to get whole numbers. The equation is below:

Posts: 30
Joined: Fri Apr 06, 2018 11:04 am

Re: Test 1 Q3

Postby NabilaNizam-1K » Sat May 05, 2018 2:07 pm


Usually, for balancing equation questions, I try balancing the least abundant element first which is Cu in this case. Hope this helps!

Alejandro Salazar 1D
Posts: 31
Joined: Fri Sep 29, 2017 7:05 am

Re: Test 1 Q3

Postby Alejandro Salazar 1D » Sat May 05, 2018 2:59 pm

It is hard to know when to use fractions especially on this one.

But if you consider a more simpler equation like C2H6 +02 --> CO2+H20

C2H6+O2 --> 2CO2+ 3H2O

C:2 C:2
H:6 H:6
O:2 O:7

There is no number you can multiply two from the oxygen on the reactant side to get 7 from the product side. I find it easier if you think of it like this. 2x=7 . Solve for x and you get 7/2 (your coefficient fraction)

C2H6+ 7/2(O2) ---> 2CO2+3H2O

Now multiply by 2 to get rid of the denominator.

2H2H6 +7O2 --> 4CO2+6H2O

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