Concept Question for #M15

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LeannaPhan14BDis1D
Posts: 57
Joined: Fri Sep 28, 2018 12:16 am

Concept Question for #M15

Postby LeannaPhan14BDis1D » Wed Oct 03, 2018 10:24 pm

When doing stoichiometry (7.55molCl2)*(2mol AlCl3/3mol Cl2) = 5.03 mol AlCl3 -- the limiting reactant
I know how to get to the answer, but I am confused conceptually as to why when you already have the mol for AlCl3 and the stoichiometric coefficient being 2.. why do we need to do more towards it to get the 5.03 mol of AlCl3?? Is it because the 2 mol AlCl3 in the equation is not the specific number of mols and it is just a ratio towards the problem before you do the extra stoichiometry?

Kimberly 1H
Posts: 63
Joined: Fri Sep 28, 2018 12:17 am
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Re: Concept Question for #M15

Postby Kimberly 1H » Wed Oct 03, 2018 10:42 pm

Yes, the 2 represents the ratio of product that can be formed. In order to find out how much product you end up with, you multiply the ratio of product:reactant, in this case, 2:3.

gwynlu1L
Posts: 62
Joined: Fri Sep 28, 2018 12:19 am

Re: Concept Question for #M15

Postby gwynlu1L » Thu Oct 04, 2018 1:15 am

Yes, you need a balanced chemical formula in order to complete limiting reactant questions, but the equation only gives molar ratios, not the specific amounts for the given question. So the 2 from the chemical equation is not the amount you have in the question, it is just part of the ratio.


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