Chem Test Balancing Equations

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705137650
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Joined: Fri Sep 28, 2018 12:18 am

Chem Test Balancing Equations

Postby 705137650 » Thu Oct 18, 2018 9:16 am

What is the balanced equaTION FOR THE COMPLETE OXIDATION OF SALICYLIC ACID (C7H6O3) WHICH PRODUCES CARBON DIOXIDE AND WATER

705137650
Posts: 16
Joined: Fri Sep 28, 2018 12:18 am

Re: Chem Test Balancing Equations

Postby 705137650 » Thu Oct 18, 2018 9:28 am

I did not add the oxygen to the reactant side which didnt allow to balance the equation which is C7H6O3 + 7O2 = 7CO2 + 3H2O

Matthew Choi 2H
Posts: 59
Joined: Fri Sep 28, 2018 12:18 am

Re: Chem Test Balancing Equations

Postby Matthew Choi 2H » Sat Oct 20, 2018 1:34 am

In order to balance this equation, you first need to recognize the reactants and products. The reactants are C7H6O3 and O2, and the products are CO2 and H2O.

So first, write the equation as follows:

C7H6O3 + O2 ---> CO2 + H2O

Now comes the part where you balance this equation. Since both the C and the H occur only once on each side, it would be a good idea to start with those.

To balance the C, add a coefficient of 7 in front of the CO2. To balance the H, add a coefficient of 3 in front of the H2O.

The resulting equation should look like this:

C7H6O3 + O2 ---> 7CO2 + 3H2O

Finally, you have to balance the O. On the right, there are 17 O's. On the left, there are 5 O's. In order to increase the number of O's on the left, you can't increase the number of moles of C7H6O3 because that will disrupt the balance of C's and H's. Therefore, you must increase the number of moles of O2 by 7 in order to make the O's balanced.

The final balanced equation will be:

C7H6O3 + 7O2 ---> 7CO2 + 3H2O


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