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Net # of moles produced

Posted: Sun Jun 30, 2019 12:09 am
by D-nice1D
The balanced equation is:
4C4H10(g) + 26O2(g) → 16CO2(g) + 20H2O(g)
How do I find the net number of moles of gas produced? My options are 6 or 5

Re: Net # of moles produced

Posted: Sun Jun 30, 2019 8:56 am
by Chem_Mod
Because all reactants and products are gases, you can count the net amount of mols of gas produced by comparing the amount of mol reactants to mol products. In this case, there are 30 total mols of gases in the reactants, while there are a total of 36 mols of gas produced in the products. So the 30 reactant gas mols get “used” to produce 36 gas mols, leaving a net 6.

Re: Net # of moles produced

Posted: Sun Jun 30, 2019 12:00 pm
by D-nice1D
Oohhh I see. Ty

Re: Net # of moles produced

Posted: Wed Oct 02, 2019 11:19 pm
by Anish Patel 4B
On the reactants side, you have 4 moles of butane reacting with 26 moles of oxygen. This produces 16 moles of carbon dioxide and 20 moles of water. All compounds are gases so you have 30 total moles of gases on the left side of the equation and 36 moles of gases on the right. 36 - 30 = 6 moles of gas produced on net.

Re: Net # of moles produced

Posted: Thu Oct 03, 2019 12:48 pm
by CNourian2H
Remember, net means overall. In this case, the net number of moles produced refers to the overall change of number of moles in the reactants to the products of the equation. You can use the simple equation net change = moles of products - moles of reactants.