## Question L.35 [ENDORSED]

Sanjana Munagala_1j
Posts: 103
Joined: Sat Aug 24, 2019 12:17 am
Been upvoted: 1 time

### Question L.35

How do you balance the equation:

FeBr2 + Na2CO3 = NaBr + CO2 + Fe3O4

005391550
Posts: 103
Joined: Thu Jul 25, 2019 12:15 am

### Re: Question L.35

I think it's supposed to be Fe3Br8 instead of FeBr2 because the result from the second equation is supposed to be the input for that equation.

Jordan Young 2J
Posts: 102
Joined: Thu Jul 25, 2019 12:17 am
Been upvoted: 1 time

### Re: Question L.35

I got 3FeBr2 + 3Na2CO3 = 6NaBr + 3CO2 + Fe3O4 for balancing the equation. I started with the Fe and then did the Br and then the Na and then the C and O.

Rita Chen 1B
Posts: 112
Joined: Sat Jul 20, 2019 12:15 am

### Re: Question L.35  [ENDORSED]

Hello!

Dr. Lavelle posted on his website something titled “Solution Manual Errors 7th Edition”. I would suggest that you could look over these and if there is anything that seems kind of off, you can always look at it for reference. For L.35, he posted that the book messed up and FeBr2 needs to be Fe3Br8.

Best,
Rita

Edmund Zhi 2B
Posts: 118
Joined: Sat Jul 20, 2019 12:16 am

### Re: Question L.35

My equations are

Fe + Br 2 -> FeBr2

3FeBr2 + Br2 -> Fe3Br8

Fe3Br8 + 4Na2CO3 -> 8NaBr + 4CO2 + Fe3O4

Assuming that the question was written incorrectly

Daniel Martinez 1k
Posts: 50
Joined: Wed Sep 18, 2019 12:16 am

### Re: Question L.35

Does anyone know how to finish this problem after balancing the equations? Thank you!

Jingyao Chen 4H
Posts: 49
Joined: Fri Sep 27, 2019 12:19 am

### Re: Question L.35

For the rest of the problem, you can see that from all of the balanced equations, for every 8NaBr to be produced, 3Fe is needed. You can then start with the dimensional analysis. First convert the ton of NaBr to grams, then use molar mass to get the number of moles in 2.5ton of NaBr. Then you can use the ratio of NaBr to Fe to get the moles of Fe. From there, you could use molar mass and unit conversion to calculate and convert the final mass of Fe needed. Hope this helped!