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Question L.35

Posted: Tue Oct 01, 2019 11:53 am
by Sanjana Munagala_1j
How do you balance the equation:

FeBr2 + Na2CO3 = NaBr + CO2 + Fe3O4

Re: Question L.35

Posted: Tue Oct 01, 2019 1:54 pm
by 005391550
I think it's supposed to be Fe3Br8 instead of FeBr2 because the result from the second equation is supposed to be the input for that equation.

Re: Question L.35

Posted: Tue Oct 01, 2019 2:07 pm
by Jordan Young 2J
I got 3FeBr2 + 3Na2CO3 = 6NaBr + 3CO2 + Fe3O4 for balancing the equation. I started with the Fe and then did the Br and then the Na and then the C and O.

Re: Question L.35  [ENDORSED]

Posted: Tue Oct 01, 2019 2:40 pm
by Rita Chen 1B
Hello!

Dr. Lavelle posted on his website something titled “Solution Manual Errors 7th Edition”. I would suggest that you could look over these and if there is anything that seems kind of off, you can always look at it for reference. For L.35, he posted that the book messed up and FeBr2 needs to be Fe3Br8.

Best,
Rita

Re: Question L.35

Posted: Thu Oct 03, 2019 12:10 pm
by Edmund Zhi 2B
My equations are

Fe + Br 2 -> FeBr2

3FeBr2 + Br2 -> Fe3Br8

Fe3Br8 + 4Na2CO3 -> 8NaBr + 4CO2 + Fe3O4

Assuming that the question was written incorrectly

Re: Question L.35

Posted: Thu Oct 03, 2019 5:04 pm
by Daniel Martinez 1k
Does anyone know how to finish this problem after balancing the equations? Thank you!

Re: Question L.35

Posted: Thu Oct 03, 2019 8:54 pm
by Jingyao Chen 4H
For the rest of the problem, you can see that from all of the balanced equations, for every 8NaBr to be produced, 3Fe is needed. You can then start with the dimensional analysis. First convert the ton of NaBr to grams, then use molar mass to get the number of moles in 2.5ton of NaBr. Then you can use the ratio of NaBr to Fe to get the moles of Fe. From there, you could use molar mass and unit conversion to calculate and convert the final mass of Fe needed. Hope this helped!