H.1 Chemical Principle 7th edition

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Ziyan Wang 3J
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Joined: Wed Sep 18, 2019 12:22 am

H.1 Chemical Principle 7th edition

Postby Ziyan Wang 3J » Thu Oct 03, 2019 4:57 pm

H.1 It appears that balancing the chemical equation Cu + SO2-> CuO + S would be simple if we could just add another O atom to the product side: Cu + SO2 -> CuO + S +O. (a) Why is that balancing procedure not allowed? (b) Balance the equation correctly.

Maya Gollamudi 1G
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Joined: Thu Jul 25, 2019 12:15 am

Re: H.1 Chemical Principle 7th edition

Postby Maya Gollamudi 1G » Thu Oct 03, 2019 5:00 pm

We can't add O to the equation because oxygen is not one of the products produced in this chemical reaction.

The correctly balanced equation would be 2Cu + SO2 --> 2CuO + S.

Vanessa Chuang 4F
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Re: H.1 Chemical Principle 7th edition

Postby Vanessa Chuang 4F » Thu Oct 03, 2019 5:01 pm

a) You can't just add elements to the product side if the reaction doesn't actually produce it (as stated in law of conservation of mass). In this case, O isn't actually produced from this equation so you wouldn't be allowed to just create it out of nowhere.
b) 2Cu +SO2-> 2CuO +S

Posts: 100
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Re: H.1 Chemical Principle 7th edition

Postby KarineKim2L » Thu Oct 03, 2019 5:02 pm

As the person above said, O is not a product of the reaction. Having 2 moles of CuO is very different from having an extra O atom. Also, typically in reactions, single O atoms are not produced.

Nyari Muchaka_Discussion 4A
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Joined: Thu Sep 19, 2019 12:17 am

Re: H.1 Chemical Principle 7th edition

Postby Nyari Muchaka_Discussion 4A » Thu Oct 03, 2019 5:03 pm

Matter cannot be created or destroyed so if oxygen isn't present(on its own) in the reactant side if cannot just show up on the product side. Hence why we balance equations, to ensure the same number of reactants is present in the products.
2Cu +SO2-> 2CuO +S

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