## H11

Philip
Posts: 100
Joined: Sat Sep 07, 2019 12:16 am

### H11

Help balance equation pls

Fe2O3 + CO = Fe3O4 + CO2

and

Fe3O4 + CO = Fe + CO2

Sartaj Bal 1J
Posts: 101
Joined: Thu Jul 25, 2019 12:17 am

### Re: H11

For the first stage of the process, I started with the Fe. Since the reactant side has 2 atoms of Fe while the products side has 3, the lowest common multiple of those two is 6. As a result, the reactant Fe2O3 receives a stoichiometric coefficient of 3 while the product Fe3O4 receives a stoichiometric coefficient of 2. After checking the rest of the reactants and products, we find that the equation is now balanced. For the second stage of the progress, I once again started with the Fe. Since the reactant Fe3O4 contains 3 Fe atoms, the product Fe receives a stoichiometric coefficient of 3. After checking the rest of the reactants and products, O still needs to be balanced. Since Fe3O4 has already been balanced, we leave it alone. Oxygen can only be changed through the CO on the reactant side and CO2 on the products. Since each of those have 1 C, we know the stoichiometric coefficient for both has to be the same. Using the guess and check method, a stoichiometric coefficient of 4 allows for 8 total oxygens on both sides.

005206171
Posts: 107
Joined: Wed Sep 18, 2019 12:20 am

### Re: H11

1) 3Fe2O3 + CO = 2Fe3O4 + CO2
2) Fe3O4 + 4CO = 3Fe + 4CO2

Ethan Lam 4A
Posts: 69
Joined: Thu Jul 11, 2019 12:17 am

### Re: H11

It is easier to balance out the elements that appear the least in the reaction in the beginning and then work your way to oxygen. Also, if it helps write out how many atoms there are on each side of the reaction.

I got 3 Fe2O3+CO ->2 Fe3O4 +CO2 and Fe3O4 + 4 CO -> 3 Fe + 4 CO2.