Module Question 19

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Aedra Li 3H
Posts: 40
Joined: Fri Aug 30, 2019 12:17 am

Module Question 19

Postby Aedra Li 3H » Tue Oct 08, 2019 2:12 pm

In the balancing chemical equation post assessment you are asked to find the net number of moles of gas produced from the combustion of 4 moles of butane. I know how to balance the equation, but am unsure as to how to determine the number of moles of gas that are produced.

Rachel Yu 1G
Posts: 113
Joined: Fri Aug 09, 2019 12:15 am

Re: Module Question 19

Postby Rachel Yu 1G » Tue Oct 08, 2019 2:20 pm

The net number of gas means the difference of moles between the gaseous products and reactants. Calculate the total stoichiometric coefficients of the reactants and products and subtract the two to find the difference in moles of gas.

MMckinney_4H
Posts: 61
Joined: Sat Sep 28, 2019 12:16 am

Re: Module Question 19

Postby MMckinney_4H » Tue Oct 08, 2019 5:55 pm

I recognized that when the equation for the combustion of butane is balanced, there are 2 moles of Butane needed, so I just multiplied the entire equation by two so it would show that for 4 moles of Butane, there would be 16 moles of Carbon Dioxide (gas) produced.
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Sofia Barker 2C
Posts: 101
Joined: Wed Sep 18, 2019 12:21 am

Re: Module Question 19

Postby Sofia Barker 2C » Wed Oct 09, 2019 10:27 am

Balancing the equation allows you to see the molar ratio between butane and carbon dioxide. The balanced equation gives a ratio of 2 moles butane to 8 moles carbon dioxide, so the combustion of 4 moles of butane would produce 16 moles of carbon dioxide according to the 2:8 ratio. 4:16 matches this ratio.


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