Balancing This Equation

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Ashley Osorio
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Joined: Thu Jul 11, 2019 12:17 am

Balancing This Equation

Postby Ashley Osorio » Tue Nov 05, 2019 1:48 pm

Write a balanced combustion reaction for solid nicotine (C10H14N2). (Hint: The reaction produces N2 gas). How can we balance it when both sides don't have Oxygen? Or does it? How are we supposed to figure this out?

Ashley Osorio
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Joined: Thu Jul 11, 2019 12:17 am

Re: Balancing This Equation

Postby Ashley Osorio » Tue Nov 05, 2019 1:49 pm

Since its a combustion, wouldn't it be C10H14N2+ O2--> N2

Michelle Le 1J
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Joined: Fri Aug 09, 2019 12:16 am

Re: Balancing This Equation

Postby Michelle Le 1J » Tue Nov 05, 2019 2:09 pm

All combustion reactions consist of O2 as one of the reactants and CO2 and H2O as the products. So for this reaction specifically, the reactants are C10H14N2 and O2, and N2, CO2, and H2O would be the products.

Jasmine Vallarta 2L
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Re: Balancing This Equation

Postby Jasmine Vallarta 2L » Tue Nov 05, 2019 2:13 pm

When it says "combustion," it is implied that you must add "+ _O2" to the reactant side of the reaction

Michelle N - 2C
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Re: Balancing This Equation

Postby Michelle N - 2C » Thu Nov 07, 2019 9:47 am

Combustion always mean that one of the reactants is O2 and the products are CO2 + H2O. Sometimes, they will add in, like in this problem, an extra product.

AKhanna_3H
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Re: Balancing This Equation

Postby AKhanna_3H » Thu Nov 07, 2019 11:07 am

Combustion reactions always have O2 as a reactant and H20 and C02 as products.

sbottomley3a
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Re: Balancing This Equation

Postby sbottomley3a » Fri Nov 08, 2019 10:24 am

Combustion reactions always indicate that the reactant will be burned in O2, and the products at minimum are CO2 and H2O, but there may be others, depending on what exactly was burned in oxygen.

anjali41
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Re: Balancing This Equation

Postby anjali41 » Fri Nov 08, 2019 11:17 am

An important step to remember is that combustion always involves Oxygen gas as a reactant, even though it is often not states in the problem. So always remember to add Oxygen gas to the chemical equation of a combustion reaction before balancing, and you should be good.

KaleenaJezycki_1I
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Re: Balancing This Equation

Postby KaleenaJezycki_1I » Fri Nov 08, 2019 1:06 pm

Ashley Osorio wrote:Write a balanced combustion reaction for solid nicotine (C10H14N2). (Hint: The reaction produces N2 gas). How can we balance it when both sides don't have Oxygen? Or does it? How are we supposed to figure this out?


Combustion reactions always are a compound +O2 and produce CO2+H20

So this should look like C10H14N2 +O2 ------> CO2+ H2O + N2 (Then you can balance it)

kendal mccarthy
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Re: Balancing This Equation

Postby kendal mccarthy » Sun Nov 10, 2019 10:54 pm

combustion equations always have O2 on the reactant side and CO2 and H2O on the other, sometimes N2 depending on the organic molecule. 2C10H14N2 +27O2 ------> 20CO2+ 14H2O + 7N2

annikaying
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Re: Balancing This Equation

Postby annikaying » Tue Nov 26, 2019 5:58 pm

Combustion implies that the reactant given is reacting with O2.

RBergtraun_3A
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Joined: Wed Feb 20, 2019 12:15 am

Re: Balancing This Equation

Postby RBergtraun_3A » Sun Dec 01, 2019 12:35 pm

You always add O2 when its a combustion reaction. Fire needs oxygen.


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