L.1 Fundamental Question

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MichaelMendozaD1F
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Joined: Wed Sep 30, 2020 9:55 pm

L.1 Fundamental Question

Postby MichaelMendozaD1F » Fri Oct 23, 2020 12:32 pm

Without using a calculator, estimate what amount of Br2 (in moles) can be obtained from 0.30 mol ClO2 in the reaction 6 ClO2(g) 1 2 BrF3(l) S 6 ClO2F(s) 1 Br2(l).

Jeffrey Doeve 2I
Posts: 110
Joined: Wed Sep 30, 2020 9:51 pm

Re: L.1 Fundamental Question

Postby Jeffrey Doeve 2I » Fri Oct 23, 2020 12:36 pm

So doing this without a calculator would be simple based on the numbers they gave us. We can use molar ratios to take 0.30 mol of ClO2 and find mol of Br2 produced with the conversion of (1 mol Br2/6 mol ClO2). So we would just take 0.30 and divide by 6 to get 0.050 mol Br2.

edward_brodell_2I
Posts: 92
Joined: Wed Sep 30, 2020 9:59 pm

Re: L.1 Fundamental Question

Postby edward_brodell_2I » Fri Oct 23, 2020 1:06 pm

Chemical equations are abstract representations of how quantities (reactants and products) are changing, and are always presented in a specific stoichimetric ratio. Use the molar ratio based on the coefficients of the balanced reaction to determine how much of a product or reactant is made by a specific number of moles of reactant or product. The chemical equation gives an important ratio of how each of the number of moles of each substance is related to one another. For example if an equation shows that 2 mol A + 3 Mol B -> 4 mol of C, then if you have 4 mol of A and want to find out how much of B or C is needed, then that is double the amount and since the ratio is 2:4 then a ratio of 4:8 tells us 8 moles of C or if trying to find out how much of the other reactant is needed, 2:3 gives us a ratio 4:6 or 6 mol of needed reactant B.


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