## Reverse Reaction, Q and K

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Leah Thomas 2E
Posts: 51
Joined: Fri Sep 29, 2017 7:06 am

### Reverse Reaction, Q and K

So when Q is greater than K that means the products are favored but Professor Lavelle stated that the reaction will never overshoot equilibrium so how can you have more products than reactants?

Nancy Dinh 2J
Posts: 59
Joined: Fri Sep 29, 2017 7:07 am

### Re: Reverse Reaction, Q and K

When Q > K, that means that you start with the product first, and then the reaction will start to occur to create more reactants. However, the reaction will never create more reactants than is required for the equilibrium. That's what Dr. Lavelle meant by "not overshooting the equilibrium". You won't get a case where you start with a forward reaction, pass the equilibrium, and then have to have a backwards reaction in order to get back to the equilibrium.

Irma Ramos 2I
Posts: 51
Joined: Fri Sep 29, 2017 7:07 am

### Re: Reverse Reaction, Q and K

Will there ever be situations in which Q is equal to K and if this is the case, which direction will the reaction proceed??

MichelleT_1L
Posts: 20
Joined: Fri Sep 29, 2017 7:04 am

### Re: Reverse Reaction, Q and K

If Q is equal to K, then the reaction is at equilibrium. At equilibrium the reaction is moving in both directions and at equal rates so there is no net change in the direction of the reaction.

Jordan Foster
Posts: 22
Joined: Fri Sep 29, 2017 7:06 am

### Re: Reverse Reaction, Q and K

Q will eventually reach the value of K, but Q is just a K value before it reaches equilibrium. Q is like a snapshot of how close the ratios are to equilibrium at a point in time.

ami patel
Posts: 20
Joined: Thu Jul 27, 2017 3:00 am

### Re: Reverse Reaction, Q and K

Q=K is perfectly equilibrium, but this is very rare and you will not come across it very often, if at all