## HW # 5G.5 7th edition

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Maggie Doan 1I
Posts: 61
Joined: Fri Sep 28, 2018 12:24 am

### HW # 5G.5 7th edition

c) Assuming that the initial pressure of X2 was .10 bar, calculate the value of K for the decomposition.

taline_n
Posts: 64
Joined: Fri Sep 28, 2018 12:17 am

### Re: HW # 5G.5 7th edition

If you're having trouble solving part c, the way I did it was by multiplying the initial pressure of X2 (.1 bar)*(1-.545), to find the pressure of X2 molecules at equilibrium (.1 bar)*(100% X2 molecules - 54.5% decomposed X2 molecules). You'll get 0.0455 bar, which is the pressure of X2.

To find the pressure of X, simply multiply 0.0455 bar x2 (because the ratio of X2:X molecules is 1:2) and you'll get 0.109 bar for the pressure of X.

Then, plug these pressures into Kp = (PX)^2/PX2 = (.109)^2/.0455 = 0.26

Eva Guillory 2E
Posts: 44
Joined: Fri Sep 28, 2018 12:22 am

### Re: HW # 5G.5 7th edition

If you look at page three of the syllabus, you will notice that 5G.5 is not included in the list of homework problems.