ICE

[jlinwashington1B]

f the value of K is less than 10^-3, what can we assume about the value ?

[Timothy_Yueh_4L]

When k < 10^-3, we assume the change in reactant is negligible therefore the value of the reactants is the same. Ex) A + B --> C: std defn of k = [C]/([A][B]). After equilibrium k = [C+x]/([A-x][B-x]), with x denoting the change in concentration, however the change is negligible therefore the equation is k = [C+x]/([A][B]).

[Mark 1D]

x can be ignored, making x equal to 0

[Amy Dinh 1A]

We can assume x is negligible unless stated otherwise.

[Jordan Lo 2A]

We can use the 5% rule to ignore x in the denominator of the fraction that you get from the ICE table

[Charles Hood Disc 1C]

A value with less than 10^-3 means that we can approximate the x value.

[isarose0]

x would be negligible because it is so small and has little effect on the concentration

[Mukil_Pari_2I]

The approximation can be utilized when solving ice problems if that condition is true.

[jocelyntzeng]

yes you can approximate but always check with the 5% rule