Module Questions- Balancing Equations


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605110118
Posts: 75
Joined: Wed Sep 18, 2019 12:21 am

Module Questions- Balancing Equations

Postby 605110118 » Wed Oct 02, 2019 10:50 pm

I came across this problem in one of the modules: During a summer camping weekend 4 moles of butane (C4H10) gas were used for cooking. Chose the right balanced equation for the combustion of 4 moles of butane gas. What is the net number of moles of gas produced?
What do they mean by net number and how would I find it?

madijohnson_4A
Posts: 40
Joined: Fri Aug 30, 2019 12:18 am

Re: Module Questions- Balancing Equations

Postby madijohnson_4A » Wed Oct 02, 2019 10:56 pm

The net number of moles is the overall moles produced in the reaction. The way you find it is to take the moles of product and subtract the moles of reactants.

pmokh14B
Posts: 107
Joined: Sat Aug 17, 2019 12:15 am

Re: Module Questions- Balancing Equations

Postby pmokh14B » Wed Oct 02, 2019 10:58 pm

4C4H10 +26O2(g) ---> 16CO2(g) + 20H2O(g)
you just balance the equation with 4 as the prefix for C4H10 and then count the moles of gas on both sides and count the ones on the right and subtract he moles of gas on the left. so for this it would be 16 + 20 - 26 = 10 moles of gas net.

Myka G 1l
Posts: 100
Joined: Fri Aug 30, 2019 12:17 am

Re: Module Questions- Balancing Equations

Postby Myka G 1l » Wed Oct 02, 2019 11:03 pm

There are 30 moles of gas for the reactants and 36 moles of gas for the products so the net moles of gas would be 36-30= 6

Darren Nguyen 1F
Posts: 60
Joined: Sat Sep 14, 2019 12:15 am

Re: Module Questions- Balancing Equations

Postby Darren Nguyen 1F » Wed Oct 02, 2019 11:30 pm

Subtract the total number of moles on the product side from the total number of moles on the reactant side.


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