Solving for K (coefficients)

[Andrea_Torres]

When solving for K to the coefficients have to be in a particular order?

[Parker Smith]

The coefficients need to be assigned to their specific molecules/compounds

[Sartaj Bal 1J]

Usually, the stoichiometric coefficients of the balanced equation are the exponent for each compound in the equilibrium equation. As long as all the products are placed in the numerator and all reactants in the denominator, the equation should work.

[MeeraBhagat]

You raise the value the concentration of a certain reactant/product to their respective coefficients in the balanced chemical equation.

[Amir Bayat]

The stoichiometric coefficients are the powers that the concentration or pressure of the product or reactant are raised to.

[Junwei Sun 4I]

The coefficients become the power of the molar concentrations in the expression for K and they have to be assigned to the specific molecules as they are in the chemical equation. For example in H2 + I2 --> 2HI,

[H2] and [I2] will have a power of 1
[HI] will have a power of 2

[RobertXu_2J]

No they do not, since multiplication exhibits commutative properties (a*b = b*a).

[gabbymaraziti]

The reactants/products don't have to be in a specific order in the calculation of K itself, but the stoichiometric coefficients should be assigned to their respective reactant/product.

[Rodrigo2J]

the coefficient becomes the exponent of whichever product or reactant it precedes. So as long as you keep the coefficient with the correct reactant or product it's assigned to you should be fine I think.

[Charysa Santos 4G]

The coefficients are attached to the particular reactant/product as you balance the equation. This coefficient becomes the exponent to the same reactant/product when calculating Q or K.

[Angela Prince 1J]

The coefficients go with the molecule it is next to in the chemical reaction. The coefficients will be the exponent the concentration of the respective molecule is raised to.

[Anthony Hatashita 4H]

Just make sure the coefficients for specific molecules remain on the same molecules as a power when calculating K.