reversing reactions


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Kaylee Clarke 1G
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reversing reactions

Postby Kaylee Clarke 1G » Sun Feb 09, 2020 8:14 pm

what happens to K when you reverse a reaction?

Cavalli_1H
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Re: reversing reactions

Postby Cavalli_1H » Sun Feb 09, 2020 8:27 pm

the K of a reverse reaction is the inverse of the forward reaction

chrisleung-2J
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Re: reversing reactions

Postby chrisleung-2J » Sun Feb 09, 2020 8:29 pm

When a reaction is reversed, K -> 1/K

Charysa Santos 4G
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Re: reversing reactions

Postby Charysa Santos 4G » Sun Feb 09, 2020 8:35 pm

The K of a reverse reaction is just the inverse of K (or 1/K)

505316964
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Re: reversing reactions

Postby 505316964 » Sun Feb 09, 2020 8:37 pm

In a forward reaction, you do products over reactants for the equilibrium equation. For the reverse it is technically reactants over products, so it makes sense that your K would be 1/K for the reverse.

Jesalynne 2F
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Re: reversing reactions

Postby Jesalynne 2F » Sun Feb 09, 2020 8:53 pm

For a reverse reaction the value of K would be 1/K which is the inverse.

WGaines_2E
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Re: reversing reactions

Postby WGaines_2E » Tue Feb 11, 2020 10:23 am

for the reverse reaction lets say Kr, Kr=1/K

ABombino_2J
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Re: reversing reactions

Postby ABombino_2J » Tue Feb 11, 2020 4:18 pm

K reverse : 1/k
K*n : K^n
K*m: K^(1/m)

Jainam Shah 4I
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Re: reversing reactions

Postby Jainam Shah 4I » Tue Feb 11, 2020 11:01 pm

If you reverse the reaction simply take the reciprocal of the the original K value so 1/K.

CalvinTNguyen2D
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Re: reversing reactions

Postby CalvinTNguyen2D » Sun Feb 16, 2020 7:00 pm

The value of K in a reverse reaction is the inverse of the forward reaction. If the value of K in a forward reaction is K, then the equilibrium constant in the reverse reaction is 1/K.

Charlene Datu 2E
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Re: reversing reactions

Postby Charlene Datu 2E » Thu Mar 12, 2020 5:30 pm

The K of the reverse reaction will be the inverse of the K of the forward reaction
Kreverse = 1/Kforward

A + B -> C
Kforward = [C]/[A][B]
Kreverse = [A][B]/[C]

aishwarya_atmakuri
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Re: reversing reactions

Postby aishwarya_atmakuri » Thu Mar 12, 2020 6:01 pm

When you reverse the reaction, you have to invert K. Therefore, for a forward reaction, the equilibrium constant is equal to K. For the reverse reaction, the equilibrium constant is equal to 1/K.

Ellis Song 4I
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Re: reversing reactions

Postby Ellis Song 4I » Thu Mar 12, 2020 6:26 pm

The k for a reversed reaction is 1/k

Jasmine W 1K
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Re: reversing reactions

Postby Jasmine W 1K » Thu Mar 12, 2020 6:48 pm

K is inversed so it becomes 1/K.

ramiro_romero
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Re: reversing reactions

Postby ramiro_romero » Thu Mar 12, 2020 6:57 pm

K is going to become inverse, so 1/K.

Adam Bustamante 1I
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Re: reversing reactions

Postby Adam Bustamante 1I » Tue Jan 05, 2021 9:56 pm

In a reverse reaction, K would become inverse, so it would be 1/K.

Shreyank Kadadi 3K
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Re: reversing reactions

Postby Shreyank Kadadi 3K » Wed Jan 06, 2021 3:18 pm

The equilibrium constant (K) for a reverse reaction is simply the inverse of the K for the forward reaction. If you think about it logically it makes sense -- a reaction that heavily favors the products would not have much reactants being formed, and vice versa.

Madison Muggeo 3H
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Re: reversing reactions

Postby Madison Muggeo 3H » Thu Jan 07, 2021 1:32 pm

Hi! In the reverse reaction, it would be 1/K since the fraction is flipped. Hope this helps :)

Rahul Sobti 1E
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Re: reversing reactions

Postby Rahul Sobti 1E » Thu Jan 07, 2021 1:37 pm

When you reverse a reaction the equilibrium constant becomes the reciprocal of K so it becomes 1/k.

Jamie Wang 3C
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Re: reversing reactions

Postby Jamie Wang 3C » Thu Jan 07, 2021 2:35 pm

reverse is 1/K and when multiplied by a constant(n), K^n

Yeonjoo Kim 2B
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Re: reversing reactions

Postby Yeonjoo Kim 2B » Thu Jan 07, 2021 2:44 pm

Just like in inverse reactions (x^-1 = 1/x), K becomes 1/K or K^-1

Jiapeng Han 1C
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Re: reversing reactions

Postby Jiapeng Han 1C » Thu Jan 07, 2021 7:35 pm

For the reverse reaction, k of forward reaction will become 1/k in the reverse reaction.

Anusha Chaudhary 1J
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Re: reversing reactions

Postby Anusha Chaudhary 1J » Thu Jan 07, 2021 7:43 pm

For the reaction P <-> R (reversible reaction), [P]/[R] will give us our K value. However, if we reverse what we define as our P and R, we would simply be flipping the equation, so the old R is on top and the old P is on the bottom. This will give us the inverse of our original K value, or simply put, 1/K.

Maya Johnson 2a
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Re: reversing reactions

Postby Maya Johnson 2a » Thu Jan 07, 2021 7:56 pm

It becomes the inverse reaction, or 1/K

sophia kosturos 2B
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Re: reversing reactions

Postby sophia kosturos 2B » Thu Jan 07, 2021 8:13 pm

For the reverse reaction, K will become its inverse or reciprocal, which is 1/K.

Lily Anne Garcia 1C
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Re: reversing reactions

Postby Lily Anne Garcia 1C » Thu Jan 07, 2021 8:51 pm

1/K

Katie Nye 2F
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Re: reversing reactions

Postby Katie Nye 2F » Thu Jan 07, 2021 10:32 pm

K becomes inverted. The way to remember this is that when an equation is reversed, what was once the products (numerator) becomes the reactants (denominator) and vice versa so the K equation would flip.

Chudi Onyedika 3A
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Re: reversing reactions

Postby Chudi Onyedika 3A » Sat Jan 09, 2021 1:00 pm

K will simply become the inverse of the reaction.

Simi Kapila_3E
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Re: reversing reactions

Postby Simi Kapila_3E » Sat Jan 09, 2021 1:02 pm

when you take a reverse reaction, you will inverse the K value (1/K) to get the new K value.

Melis Kasaba 2B
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Re: reversing reactions

Postby Melis Kasaba 2B » Sat Jan 09, 2021 1:18 pm

The equilibrium constant for a reverse reaction is the reciprocal of the one for the forward reaction, so it would be 1/K.

Jason Knight - 1F
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Re: reversing reactions

Postby Jason Knight - 1F » Sat Jan 09, 2021 3:33 pm

An easy way to calculate the K value for the reverse reaction is to find the reciprocal of the forward reaction, which is K = (1/Forward). I find this calculation quick and simple instead of flipping the formula to K = (R)/(P) and plugging in values from there.

Kayla Booker 1F
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Re: reversing reactions

Postby Kayla Booker 1F » Sat Jan 09, 2021 4:34 pm

When you reverse the reaction, k is inverted so it would then be 1/k or k^-1

Karen Elrayes 1L
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Re: reversing reactions

Postby Karen Elrayes 1L » Sat Jan 09, 2021 10:55 pm

Reversing the reaction flips all Reactants to products and vice versa, thus when u are calculating K the top and bottom are flipped which is why we put 1/k when we reverse the reaction.

Carlos Martinez 2K
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Re: reversing reactions

Postby Carlos Martinez 2K » Sat Jan 09, 2021 11:15 pm

K becomes 1/K when you reverse a reaction. This shows that the concentrations are the same during. equilibrium. This. can also be written as K-1

Mari Williams 1K
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Re: reversing reactions

Postby Mari Williams 1K » Sun Jan 10, 2021 1:46 pm

Reverse reaction move towards the reactants, right? Does K only refer to the forward reaction or can we specify K(reverse)

Hana Sigsbee 3B
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Re: reversing reactions

Postby Hana Sigsbee 3B » Sun Jan 10, 2021 1:48 pm

when a reaction is reversed K is inversed as 1/K

Daniela Santana 2L
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Re: reversing reactions

Postby Daniela Santana 2L » Sun Jan 10, 2021 3:03 pm

When you reverse a reaction, the K value of it is the inverse of the forward reaction. So to find K for the reverse reaction solve for 1/K.

Andy Hernandez
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Re: reversing reactions

Postby Andy Hernandez » Sun Jan 10, 2021 6:57 pm

It is just the inverse of K or 1/K

Adrienne Chan 1G
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Re: reversing reactions

Postby Adrienne Chan 1G » Sun Jan 10, 2021 7:00 pm

We get the inverse of K, this is calculated as 1/K.

MichaelRaad_1F
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Re: reversing reactions

Postby MichaelRaad_1F » Sun Jan 10, 2021 7:03 pm

The K of a reverse reaction is the inverse of the K for the forward reaction.

Karen Zheng_2K
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Re: reversing reactions

Postby Karen Zheng_2K » Sun Jan 10, 2021 7:05 pm

When you reverse an action, K becomes 1/K!

joshtully
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Re: reversing reactions

Postby joshtully » Sun Jan 10, 2021 8:00 pm

When a reaction is reversed, K becomes 1/K.

Melanie Lin 3E
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Re: reversing reactions

Postby Melanie Lin 3E » Sun Jan 10, 2021 8:49 pm

Hi! The K of the reverse reaction will be the reciprocal of the K of the forward reaction (1/K).

Jack Kettering 3D
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Re: reversing reactions

Postby Jack Kettering 3D » Sun Jan 10, 2021 8:56 pm

The k value for the reversed reaction is just the inverse of k, 1/k

RaniyaFeroz_1E
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Re: reversing reactions

Postby RaniyaFeroz_1E » Sun Jan 10, 2021 8:59 pm

K would just be 1/K when you reverse a reaction. I think Dr.Lavelle had an example of this in his first lecture.

Isaias Gomez D3A
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Re: reversing reactions

Postby Isaias Gomez D3A » Sun Jan 10, 2021 9:04 pm

When a reaction is reversed, K -> 1/K

just the inverse :)

Hannah Lechtzin 1K
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Re: reversing reactions

Postby Hannah Lechtzin 1K » Sun Jan 10, 2021 9:06 pm

The K of a reverse reaction is just the inverse of K (1/K).

Francesca_Borchardt_2D
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Re: reversing reactions

Postby Francesca_Borchardt_2D » Sun Jan 10, 2021 9:41 pm

I was confused on this as well, all the above replies really helped me.. Thank you everyone :)!

Ashley Wagner 2A
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Re: reversing reactions

Postby Ashley Wagner 2A » Sun Jan 10, 2021 9:43 pm

The reverse reaction K value is just the inverse of K for the forward reaction. Therefore it would be 1/K

Aria Movassaghi 1A
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Re: reversing reactions

Postby Aria Movassaghi 1A » Sun Jan 10, 2021 9:46 pm

It would become 1/k

LeahSWM 2E
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Re: reversing reactions

Postby LeahSWM 2E » Sun Jan 10, 2021 10:37 pm

When you reverse the reaction of K, the value becomes 1/K.

Zihan Liu 2K
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Re: reversing reactions

Postby Zihan Liu 2K » Sun Jan 10, 2021 10:42 pm

It would be 1/K because in a forward reaction, K = [P]/[R]. In a reverse reaction, the product in the forward reaction would become the reactant in the reverse reaction, and the same goes with the reactant in the forward reaction. Therefore, the K for the reverse reaction equals to [R]/[P]. [R]/[P] is the 1/([P]/[R]). Therefore, it would be 1/K.

Chinmayi Mutyala 3H
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Re: reversing reactions

Postby Chinmayi Mutyala 3H » Sun Jan 10, 2021 10:43 pm

K is products over reactants so if you use the reverse reaction, K would be the reactants over the products. That's why K (reverse) is 1/K (forward)

Gustavo_Chavez_1K
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Re: reversing reactions

Postby Gustavo_Chavez_1K » Sun Jan 10, 2021 11:12 pm

When reversing a reaction, the value of K becomes the inverse of the forward reactions K (1/K).

Lorraine Medina 3E
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Re: reversing reactions

Postby Lorraine Medina 3E » Wed Jan 13, 2021 11:22 pm

When K is reversed, it becomes the inverse of the forward reaction, therefore 1/K. Hope this helps!

Akriti Ratti 1H
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Re: reversing reactions

Postby Akriti Ratti 1H » Wed Jan 13, 2021 11:27 pm

In this case, K would be inversed. So it would go from K to 1/K.

Tiao Tan 3C
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Re: reversing reactions

Postby Tiao Tan 3C » Thu Jan 14, 2021 1:23 am

K would also be inversed. It will become 1/K because the equilibrium constant for the inversed reaction is adopting a reversed product-reactant relationship.

ShinwooKim_3E
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Re: reversing reactions

Postby ShinwooKim_3E » Sat Jan 16, 2021 1:31 pm

K becomes the inverse, 1/K.

Sukhkiran Kaur 3I
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Re: reversing reactions

Postby Sukhkiran Kaur 3I » Sat Jan 16, 2021 2:31 pm

It would be inverse K, so 1/K.

Lung Sheng Liang 3J
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Re: reversing reactions

Postby Lung Sheng Liang 3J » Sat Jan 16, 2021 3:17 pm

The K for reverse reactions would be 1/K

Brian Nguyen 2I
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Re: reversing reactions

Postby Brian Nguyen 2I » Sun Jan 17, 2021 7:19 pm

When you reverse a reaction, K is just equal to the reciprocal of K instead. This is 1 divided by K.

Vivian_Le_1L
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Re: reversing reactions

Postby Vivian_Le_1L » Sun Jan 17, 2021 7:41 pm

The K of the reverse reaction would be the inverse. 1/K or K-1.
EX. [A] + [B] <-> [C]
KFORWARD = [C] / [A][B]
KREVERSE =[A][B] / [C] , which is the reciprocal/inverse of the forward reaction.

Megan ODonnell 3F
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Re: reversing reactions

Postby Megan ODonnell 3F » Sun Jan 17, 2021 7:46 pm

It is the inverse of the forward reaction, so you would take 1/K to find the reverse constant.

Gwen Casillan 3E
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Re: reversing reactions

Postby Gwen Casillan 3E » Sun Jan 17, 2021 7:47 pm

It would be the inverse of K, so 1/K.

Jared Limqueco 3E
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Re: reversing reactions

Postby Jared Limqueco 3E » Sun Jan 17, 2021 8:12 pm

In a reverse reaction, you take the reciprical, so 1/K

305405193
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Re: reversing reactions

Postby 305405193 » Sun Jan 17, 2021 9:36 pm

just like how you reversed the reaction, you would have k inversed so it would be 1/K

305405193
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Re: reversing reactions

Postby 305405193 » Sun Jan 17, 2021 9:38 pm

One good video that expressed an example of reversing a reaction was on this link https://www.youtube.com/watch?v=aJ0KNQ5-KaI

Bai Rong Lin 2K
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Re: reversing reactions

Postby Bai Rong Lin 2K » Sun Jan 17, 2021 9:53 pm

it basically changes k > 1/k.

Jack Kettering 3D
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Re: reversing reactions

Postby Jack Kettering 3D » Sun Jan 17, 2021 9:56 pm

K for a reversed reaction is equal to the inverse of the forward reaction's k.

Mansi Solanki 3A
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Re: reversing reactions

Postby Mansi Solanki 3A » Sun Jan 17, 2021 9:58 pm

When you reverse the reaction, the K now becomes 1/K which would essentially be the inverse of the original K.

Yeonjoo Kim 2B
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Re: reversing reactions

Postby Yeonjoo Kim 2B » Mon Jan 18, 2021 11:58 am

K becomes 1/K or K^-1

Colin Squire 3B
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Re: reversing reactions

Postby Colin Squire 3B » Mon Jan 18, 2021 12:43 pm

When the reaction of K is reversed, K becomes the inverse of the reaction, 1/K.

alebenavides
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Re: reversing reactions

Postby alebenavides » Mon Jan 18, 2021 12:49 pm

when K is reversed it becomes the inverse

SahajDole_1C
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Re: reversing reactions

Postby SahajDole_1C » Mon Jan 18, 2021 2:02 pm

When you reverse a reaction, the k value is inversed so it would be 1/K

Faith Lee 2L
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Re: reversing reactions

Postby Faith Lee 2L » Mon Jan 18, 2021 3:05 pm

The K for the reverse reaction is the inverse (1/K) of the forward reaction, and vice versa :)

Laura 3l
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Re: reversing reactions

Postby Laura 3l » Mon Jan 18, 2021 4:25 pm

When you reverse the reaction, K simply becomes the inverse of itself (1/K).

Faaizah Arshad 1H
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Re: reversing reactions

Postby Faaizah Arshad 1H » Mon Jan 18, 2021 7:28 pm

When you reverse a reaction, you should take the inverse of K, which means computing 1/K.

Cecilia Cisneros 1F
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Re: reversing reactions

Postby Cecilia Cisneros 1F » Mon Jan 18, 2021 7:52 pm

For a reverse reaction, you should take the inverse of the original K in order to find the equilibrium constant (AKA: new K value)

Sejal Parsi 3K
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Re: reversing reactions

Postby Sejal Parsi 3K » Tue Jan 19, 2021 1:30 am

K becomes the inverse: 1/K.

Samantha Lee 1A
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Re: reversing reactions

Postby Samantha Lee 1A » Tue Jan 19, 2021 9:36 am

When you reverse reactions, you are going from products to reactants. Because of that, you would get K = 1/K because K is products over reactants and you would want the reverse, reactants over products because that is the new products/reactants.

Use inverse K (1/k, or K^-1) for a reverse reaction. Think of doing the problem backwards, flip the K.

Namita Shyam 3G
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Re: reversing reactions

Postby Namita Shyam 3G » Wed Jan 20, 2021 11:07 am

When a reaction is reversed, we will get 1/K.

Gwirnowski 3B
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Re: reversing reactions

Postby Gwirnowski 3B » Sat Jan 23, 2021 8:30 pm

for the reverse reaction, the inverse of K is used, or 1/K

Joel Meza 3I
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Re: reversing reactions

Postby Joel Meza 3I » Sun Jan 24, 2021 1:33 pm

When you have a reaction A+B-->C and have its K value and then reverse the reaction to C-->A+B, the K value of this reverse reaction will be the inverse of the first K value.

Tatyana Bonnet 2H
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Re: reversing reactions

Postby Tatyana Bonnet 2H » Sun Jan 24, 2021 1:39 pm

When you reverse a reaction you take the inverse of K, 1/K, because you are essentially just flipping the products and reactants of the reaction. So in the reverse reaction the products are the reactants from the original reaction and the reactants are the products.


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