5I.3

$PV=nRT$

Ayesha Aslam-Mir 3C
Posts: 113
Joined: Wed Sep 30, 2020 9:43 pm

5I.3

Would you use pv=nRT to solve this? You're not given a volume, so would we assume 1 L?

Selena Quispe 2I
Posts: 124
Joined: Wed Sep 30, 2020 10:01 pm
Been upvoted: 3 times

Re: 5I.3

Hi! I don't think you would need to use PV= nRT. You would look at the Table and find that your Kc is 160 and then input the concentrations of [HI] and [I2] in the equilibrium constant equation to solve for x which is [H2].

Darlene Lien 3E
Posts: 117
Joined: Wed Sep 30, 2020 9:37 pm

Re: 5I.3

Hi, I agree with the above comment. You use Kc=160 from Table 5G.2 and set up your equilibrium ratio accordingly. :)

BrittneyMyint1D
Posts: 110
Joined: Wed Sep 30, 2020 9:59 pm
Been upvoted: 3 times

Re: 5I.3

Hello, as those above said, since they provide K and the equilibrium concentrations for HI and I2, you can solve H2 by setting up the equilibrium constant ratio, substituting in the values give, and solving for H2 that way. Hope this helps!

Nishka Vipul 1J
Posts: 46
Joined: Thu Dec 17, 2020 12:18 am

Re: 5I.3

Ayesha Aslam-Mir 3C wrote:Would you use pv=nRT to solve this? You're not given a volume, so would we assume 1 L?

Hi Ayesha,

As others have mentioned above, this question asks you to refer to Table 5G.2 in order to get the Kc value! You can then use this value and set it equal to the K equation and solve for [H2].