5I.3


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Ayesha Aslam-Mir 3C
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Joined: Wed Sep 30, 2020 9:43 pm

5I.3

Postby Ayesha Aslam-Mir 3C » Wed Jan 20, 2021 12:00 am

Would you use pv=nRT to solve this? You're not given a volume, so would we assume 1 L?

Selena Quispe 2I
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Re: 5I.3

Postby Selena Quispe 2I » Wed Jan 20, 2021 12:11 am

Hi! I don't think you would need to use PV= nRT. You would look at the Table and find that your Kc is 160 and then input the concentrations of [HI] and [I2] in the equilibrium constant equation to solve for x which is [H2].

Darlene Lien 3E
Posts: 117
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Re: 5I.3

Postby Darlene Lien 3E » Wed Jan 20, 2021 12:45 am

Hi, I agree with the above comment. You use Kc=160 from Table 5G.2 and set up your equilibrium ratio accordingly. :)

BrittneyMyint1D
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Re: 5I.3

Postby BrittneyMyint1D » Wed Jan 20, 2021 12:55 am

Hello, as those above said, since they provide K and the equilibrium concentrations for HI and I2, you can solve H2 by setting up the equilibrium constant ratio, substituting in the values give, and solving for H2 that way. Hope this helps!

Nishka Vipul 1J
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Re: 5I.3

Postby Nishka Vipul 1J » Wed Jan 20, 2021 6:32 pm

Ayesha Aslam-Mir 3C wrote:Would you use pv=nRT to solve this? You're not given a volume, so would we assume 1 L?


Hi Ayesha,

As others have mentioned above, this question asks you to refer to Table 5G.2 in order to get the Kc value! You can then use this value and set it equal to the K equation and solve for [H2].

I hope this was helpful!


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