Reversing Reactions

[Shana Patel 1C]

What happens to K when you reverse a reaction?

[Alvin Lai 3J]

The K for a reverse equation is the reciprocal of K, so 1/K. Hope this helps!

[Julianna_flores3E]

It would be 1/K

[ALee_1J]

When you reverse a reaction, K is flipped. Ie. K_reverse = 1/K_forward

[Sandy Lin 1L]

It would just be the reciprocal 1/K because the original K is the forward reaction's products over reactants. The reverse would be reactants over products of the forward reaction.

[Kat Stahl 2K]

When you reverse a reaction you take the reciprocal of K so 1/K.

[Isabella Chou 1A]

Another way you can think of this is that when you reverse a reaction, you are multiplying the stoichiometric coefficients of the equation by -1, so the new K is K^-1. This is the same as how if you double the stoichiometric coefficients, the new K is K^2.

[Brianna Chen 3F]

When you reverse a reaction, the proportions of K are flipped which is why you take the inverse of K (1/K).

[Bryan Le 2K]

To calculate the K for a reverse reaction, you would take the 1/K of the forward reaction because the numerator and reactants are now switched.

[Vivian_Le_1L]

The K of the reverse reaction is the inverse of the forward reaction.

A + B <-> C
Forward reaction: K = [C] / [A][B]
Reverse Reaction: K = [A][B] / [C] = 1/K

[Bai Rong Lin 2K]

it is 1/k

[Diana Aguilar 3H]

When you reverse a reaction, you would take the reciprocal of K so it would be 1/k.

[Hailey Kang 2K]

Hi! When you reverse a reaction, K becomes the reciprocal, so you would calculate 1/K.

[SamayaJoshi1A]

It is 1/K. Also remember that K is going to be different than enthalpy, in enthalpy its a sign change.

[Edwin Liang 1I]

The K for a reverse reaction is 1/K

[John Antowan 1K]

The K in a reverse reaction is the reciprocal of K, or 1/K.

[Hannah Lechtzin 1K]

K is the reciprocal of its forward reaction value. It'll just be 1/K for the reverse reaction.

[Dane_Beasley_1E]

When reversing the reaction you would use the reciprocal of K.

[Lauren Sarigumba 1K]

When K represents the forward reaction, then 1/K represents the reverse reaction.

[kentbui1d]

When a reaction is reversed the new K value is K^-1 or 1/K.

[MariaCassol1L]

When you reverse a reaction that you know K, you can assume that the equilibrium constant for that reaction will be 1/K if the temperature remains the same.

[Ashley Wagner 2A]

it would be the reciprocal of K, 1/K

[Andy Hon 3E]

When you reverse a reaction, the k value will simply be the inverse of the original forward reaction. 1/k or k^-1

[Anvy 1G]

usually they just simply inverse and from k it goes to 1/k and then we can solve for it from there.

[Ivy Tan 1E]

When you reverse a reaction, the equilibrium constant of the reverse reaction is the reciprocal of the equilibrium constant of the forward reaction (Kreverse = 1/Kforward). Hope this helps!

[Michelle Nguyen 3F]

When you reverse an equation, K becomes 1/K!

[Sreeram Kurada 3H]

K would change to 1/K

[Lily Anne Garcia 1C]

1/k!

[Gicelle Rubin 1E]

i know it's repetitive but as you already know, it's 1/K :)

[Sejal Parsi 3K]

As everyone said above, it would be 1/K.

[James_Hankee_1C]

When a reaction is reversed the proportions of K are flipped so you take the inverse of K (1/K)

[Jose Miguel Conste 3H]

when reversing the reaction, it would be 1/K

[Siwa Hwang 3G]

1/K !

[Jacob Schwarz-Discussion 3I]

When you reverse a reaction, it turns into 1/K.

[Brianna Chen 3F]

When you reverse a reaction, K becomes 1/K.

[Ismar Zamora]

1/k!

[AlbertGu_2C]

Additionally, when multiplying a whole equation, its K is raised that power as well.

[Taha 2D]

it would be the reciprocal (1/k)

[Xiang Li 2F]

I think it would become 1/K!

[Allison Peng 1D]

When you reverse a reaction the new reaction coefficient is the reciprocal of the original reaction coefficient. This makes sense if you consider writing K with the new "products" and "reactants"

[Jordyn Lee 1J]

Hi, when you reverse a reaction K would become the reciprocal of itself, so it would be 1/K.

[Reece Fong 2k]

The reverse of a reaction reverses which group is the products and which are the reactants. So for R <--> P, instead of P/R, K would be R/P for the reverse reaction. That means K would now be 1/K of the forward reaction.

[Hannah Carsey 1B]

For the forward reaction, K = [products] / [reactants]. The K for the reverse reaction equals the inverse of the equilibrium constant (K) for the forward reaction. K forward = 1 / K reverse.

[Diya Kar]

Can someone clarify the following manipulations to the equilibrium constant Kc?
- Reverse reaction: 1/Kc
- Multiplying reaction by a coefficient: (Kc)^coefficient
- Summing 2 reactions with difference K constants: K(K)

Thanks in advance.

[Michelle Argueta 1E]

The K for a reverse equation is the reciprocal of K which would be 1/K.

[Srikar_Chintala_1E]

K would be now become the inverse of what it was initially. Hence, it would be 1/K because the expression would be flipped once you reverse the reaction.

[Natalie Coughlin 1I]

A reverse reaction means you take the reciprocal of K, as calculating this K value would mean that the numerator and denominator are swapped. Therefore, K for a reverse reaction would just be 1/k.

[Sidharth Paparaju 3B]

For the reverse reaction, the products are now reactants and the reactants are now products, meaning that k is "flipped," or 1/K.

[KyleNagasawaDisc3C_Chem 14B2022W_]

As many others have written, a forward reaction equilibrium constant K can be used to calculate that for the reverse by determining the reciprocal of K (K' = K^-1). In terms of how this can be rationalized (not memorized), the "reverse" equilibrium mixture would have products in place of reactants and vice versa compared to the "forwards" equilbrium. As such, the numerators and denominators are flipped.

[Coraly De Leon]

It will shift to 1/K.

[Milan Vognarek 1A]

The K value will change to its inverse: 1/K. This makes sense mathematically since the numerators and denominators will be switched as the products and reactants are switched, repectively.

[Madison Rhynhart 3H]

When you reverse a reaction just as the products will move to the denominator so will K because K represents products/reactants thus reactants/products would indicate 1/K.

[Prithvi Raj 3E]

When you reverse a reaction, your equilibrium constant turns into 1/K, K being the constant of the forward reaction.

[Ivy Vo Dis 1C]

Reversing a reaction means that the reaction would switch the reactants with the products, and the products with the reactants. This means that K would go from being [products]/[reactants] to being [reactants]/[products]. To calculate this more efficiently, the new K of the reverse reaction would be 1/K from the initial reaction.

[Martha Avila 1I]

Hello! When you reverse a reaction you are essentially doing the same thing but flipping the products and reactants. This in turn will lead you to find the inverse of your K in order to get the reverse reaction value. You would find this by using 1/K. Hope this helps.

[Aanjaneyaa]

K is not the same value. It becomes 1/K.

[Samantha Loc 1B]

When the reaction is reversed, the equilibrium constant becomes 1/Kc

[Ruben Adamov 1E]

In a reverse reaction, K becomes 1/K.
Hope this helps!

[Brandon Padilla 2L]

K becomes 1/K as you take the reciprocal once the reaction is reversed.

[Allen Mayo 1E]

Prof. Lavelle stated this on Lecture 1, it's around the midpoint, maybe a little less than the midpoint of the lecture. He explained that the reverse of the reactions eq constant should just be the inverse of K so 1/K. He shows that it is pretty much flipping the structure of the equilibrium constant equation by changing place of the reactants and the products.

[Julie Mai 1K]

Hello!

When you reverse a reaction, K becomes 1/K. Hope this helped!

[Brenda Tran 3C]

When you reverse a reaction, the equilibrium constant would be the inverse of K (1/K).

[Erin Chin 1L]

Hello! When you reverse a reaction, the equilibrium constant would be the inverse of K, so 1/K. You flip the products and reactants.

[Ashley Wilson 2L]

If you are looking at the reverse reaction, take the reciprocal of K. This means the K for the reverse reaction is 1/K.

[Holly Do 2J]

For the reverse reaction, the K of that will be the reciprocal of the forward reaction (1/K)

[briana lay 3c]

Hello!

When you reverse a reaction, the products of the old reaction become the new reactants (vice versa for the old reactants). Using the K formula, it would mean that the K value of the reverse reaction would be the reciprocal (1/K) of the old reaction. Hope this helps!

[Jessica Li 1G]

When you reverse a reaction, the K will become it's reciprocal, so 1/K

[Ally M]

1/K :) thank you!

[Aneesha_Nema_3C]

The reciprocal would be used when reversing reactions so it would be 1/K!