Sapling week 3/4 #15

[Brianna Martilla 1C]

I was having trouble with this problem:

2NaN3(s) 2Na(s) + 3N2(g)

Calculate the value of work for the system if 21.1 g NaN3 reacts completely at 1.00 atm and 22 ∘ C.

I think I'm supposed to use PV=nRT, however I'm not sure how to find the number of moles for N2 to plug in for n.

[Arti_Patel_3H]

You have to find the moles of NaN₃ and then multiply that by (3 moles N₂/ 2 moles NaN₃). This gives you moles of N₂ which you can plug in for n in the PV=nRT equation.

[Amanda Chang 2B]

Because you're told that NaN3 reacts completely, you can you stoichiometry to find the number of moles of N2 that is produced. With that, you would use the ideal gas law to find its volume, and then you can solve for work. Hope this helps!

[Will Skinner]

First used the mass of NaN3 and stoichiometry to determine the number of moles of N2 produced. Then find the volume of N2 using the ideal gas law. Finally to solve for work, you use w = -PΔV. Then convert to joules.

[Nan_Guan_1L]

you can use the moles of NaN3 to calculate the moles of N2 since according to the chemical reaction their mole ratio is 2:3. you can find the moles of NaN3 by dividing its mass by its molar mass

[Katelynn Shaheen 2C]

Find the moles of Na2 by using moles of NaN3.

[Matlynn Giles 2E]

you should find the moles of Na2 by using moles of NaN3

[Natalie Do 3F]

w=−pV
p=1.013×10^5
V=11.25x10^-3
so -pV=w=-1139