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Kim Vu 2G
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Joined: Fri Sep 25, 2015 3:00 am


Postby Kim Vu 2G » Sat Nov 28, 2015 11:04 pm

For homework question 11.67."The reaction 2HCL<->H2 + Cl2 has K=3.2 x 10^-34 at 298 K. The initial partial pressures are H2, 1 bar; HCl 2 bar and Cl2 at 3 bar at equilibrium there is 1 mol H2. What is the volume of the container?" Why is there a new initial state of pressure in this equation?

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Joined: Fri Sep 25, 2015 3:00 am

Re: Equilibruim

Postby TiffanyDinh1C » Sun Nov 29, 2015 5:29 pm

For this problem, since K is less than 1, there are more reactants at equilibrium so the reaction is shifted towards the products. Therefore, we can re-write the new initial amounts as 4 (HCl), 0 (H2), 2 (Cl).

2HCl--> H2 + Cl2
I 2 1 3
I (New) 4 0 2
C -2x +x +x
E 4-2x x 2+x

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