Partial Pressures in Bar/K vs Kc

[Aanchal Kasargod 1H]

Hi! I was doing some of the extra homework problems in the textbook today, and I came across the topic of partial pressures being converted to bar when calculating Kp vs Kc. I got a little confused with some of the conversions like with the equation K = (RT)^(n) Kc. I was wondering if we'd have to do conversion like this on the exams/the best way to go about it?

[Sarah Yang 1B]

Since we did not go over this conversion in lecture, I do not believe we will need it for the upcoming midterm. Also, none of the practice textbook problems required this equation, so we probably do not need to use it for exams.

[Rochelle Mosley 2D]

On top of the previous reply, I remember professor saying that we will interchangeably use atm and bar so for our class they are essentially the "same" so I don't believe that is something you'll need to worry about.

[505736451]

I'm pretty sure it doesn't matter as long as you are using only atm or only Barr. As long as everything is under the same unit, the ratios should be accurate.