Textbook problem 5.I.1
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Carson Yoshida 3H
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Kylie Heering 1D
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Re: Textbook problem 5.I.1
Hi,
There is not really a need for the ICE box here because they give us the equilibrium concentrations already. An ICE box is more appropriate when we are working with concentrations not in equilibrium (e.i. "initial" or "added").
Here, we should make an equation to solve for Br2 by first setting it up as if we are solving for Kc. So: [BrCl]^2/[Br2][Cl2]= K
Then, plug in what is given. (0.145)^2/(0.495)(x)= 0.031
Solve for x, and that will be your equilibrium concentration of Br2
There is not really a need for the ICE box here because they give us the equilibrium concentrations already. An ICE box is more appropriate when we are working with concentrations not in equilibrium (e.i. "initial" or "added").
Here, we should make an equation to solve for Br2 by first setting it up as if we are solving for Kc. So: [BrCl]^2/[Br2][Cl2]= K
Then, plug in what is given. (0.145)^2/(0.495)(x)= 0.031
Solve for x, and that will be your equilibrium concentration of Br2
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