3F.5 part c)

Moderators: Chem_Mod, Chem_Admin

Posts: 51
Joined: Fri Aug 30, 2019 12:17 am

3F.5 part c)

Postby LReedy_3I » Wed Nov 20, 2019 5:06 pm

In part C of question 3F.5, why exactly are the London forces in CHI3 stronger than those in CHF3? Is it because of the size of the atoms or the polarizability?

Posts: 221
Joined: Fri Aug 09, 2019 12:16 am

Re: 3F.5 part c)

Postby Brian_Ho_2B » Wed Nov 20, 2019 5:07 pm

Yes, the difference in the relative strengths of their LDF is due to their differences in polarizability. Because iodine is larger and has more electrons, it's more polarizable than chlorine, which is why the LDF in the compound with iodine is stronger and thus has a higher boiling point.

Cooper Baddley 1F
Posts: 100
Joined: Wed Sep 18, 2019 12:19 am

Re: 3F.5 part c)

Postby Cooper Baddley 1F » Wed Nov 20, 2019 5:08 pm

Both size means more electrons which means more polarizability which then leads to stronger London forces

Return to “Interionic and Intermolecular Forces (Ion-Ion, Ion-Dipole, Dipole-Dipole, Dipole-Induced Dipole, Dispersion/Induced Dipole-Induced Dipole/London Forces, Hydrogen Bonding)”

Who is online

Users browsing this forum: No registered users and 1 guest