3F.5 part c)

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3F.5 part c)

Postby LReedy_3C » Wed Nov 20, 2019 5:06 pm

In part C of question 3F.5, why exactly are the London forces in CHI3 stronger than those in CHF3? Is it because of the size of the atoms or the polarizability?

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Re: 3F.5 part c)

Postby Brian_Ho_2B » Wed Nov 20, 2019 5:07 pm

Yes, the difference in the relative strengths of their LDF is due to their differences in polarizability. Because iodine is larger and has more electrons, it's more polarizable than chlorine, which is why the LDF in the compound with iodine is stronger and thus has a higher boiling point.

Cooper Baddley 1F
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Re: 3F.5 part c)

Postby Cooper Baddley 1F » Wed Nov 20, 2019 5:08 pm

Both size means more electrons which means more polarizability which then leads to stronger London forces

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